The gravitational force between Mars and the Sun is 
Explanation:
The magnitude of the gravitational force between two objects is given by  the equation:
 
where
 is the gravitational constant
 is the gravitational constant
m1, m2 are the masses of the two objects
r is the separation between them
In this problem, we have:
 is the mass of the Sun
 is the mass of the Sun
 is the mass of Mars
 is the mass of Mars
 is the average distance Mars-Sun
 is the average distance Mars-Sun
Substituting into the equation, we find the gravitational force:

So, the closest answer is

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To place the poles of a 1. 5 v battery to achieve the same electric field is 1.5×10−2 m
The potential difference is related to the electric field by:
∆V=Ed
where,
∆V is the potential difference
E is the electric field
d is the distance
what is potential difference?
The difference in potential between two points that represents the work involved or the energy released in the transfer of a unit quantity of electricity from one point to the other.
We want to know the distance the detectors have to be placed in order to achieve an electric field of
E=1v/cm=100v/cm
when connected to a battery with potential difference
∆v=1.5v
Solving the equation,we find



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Explanation :
It is given that,
Mass of the car, m = 1000 kg               
Force applied by the motor, 
The static and dynamic friction coefficient is, 
Let a is the acceleration of the car. Since, the car is in motion, the coefficient of sliding friction can be used. At equilibrium,




So, the acceleration of the car is  . Hence, this is the required solution.
. Hence, this is the required solution.
 
        
             
        
        
        
Answer:
75 m
Explanation:
The horizontal motion of the projectile is a uniform motion with constant speed, since there are no forces acting along the horizontal direction (if we neglect air resistance), so the horizontal acceleration is zero.
The horizontal component of the velocity of the projectile is

and it is constant during the motion;
the total time of flight is
t = 5 s
Therefore, we can apply the formula of the uniform motion to find the horizontal displacement of the projectile:
