Answer:
259.497 mg, 58.84%
Explanation:
BaSO₄ → Ba²⁺ + SO₄²⁻
to calculate the mole of BaSO₄
mole BaSO₄ = mass given / molar mass = 403 mg / 233.38 g/mol = 1.7268 mol
comparing the mole ratio
1.7268 mol of BaSO₄ yields 1.7268 mol of Ba²⁺
403 mg BaSO₄ yields ( 1.7268 × 137.327 ) where 137.327 is the molar mass of Barium mol of Ba²⁺
441 mg BaSO₄ will yield ( 1.7268 × 137.327 × 441 mg ) / 403 mg = 259 .497 mg
mas percentage of the Barium compound = 259 .497 mg / 441 mg × 100 = 58.84%
cesium sulfate solubility decreases with decrease in temperature (answer C) change in temperature led to the change in kinetic energy.The lower kinetic energy the lower the solubility.Decrease in temperature led to lower kinetic energy hence lowering the solubility.
Answer:
Salt and water
Explanation:
The reaction of an acid and a base forming a salt and water.
10 / (7.89) (2)
molarity equation is M = Moles of solute / Liters of solution
7.89 = Moles of solute / 2
(7.89)(2). The question asks for the molar mass which is defined as g/mol. Dividing would give you the unknown compound.
<span>MM = 10g / (7.89)(2)</span>
Answer:
volume = 0.288 L
Explanation:
To find the volume, you need to (1) convert grams LiBr to moles LiBr (via molar mass) and then (2) calculate volume (via molarity equation). It is important to arrange the ratios in a way tat allows for the cancellation of units (desired units in the numerator).
<u>(Step 1)</u>
Molar Mass (LiBr): 6.9410 g/mol + 79.904 g/mol
Molar Mass (LiBr): 86.845 g/mol
100 grams LiBr 1 mole
----------------------- x ------------------ = 1.15 moles LiBr
86.845 g
<u>(Step 2)</u>
Molarity (M) = moles / volume (L)
4 M = 1.15 moles / volume
(4 M) x volume = 1.15 moles
volume = 1.15 moles / 4 M
volume = 0.288 L
