Answer:
Yes
Explanation:
(a)
Yes, the radiating electric field lines around a stationary charged particle are straight lines when the particle is stationary.
Answer:
<h2>3.36J</h2>
Explanation:
Step one:
given data
mass m= 1.3kg
distance moved s= 2.8m
opposing frictional force= 0.34N
assume g= 9.81m/s^2
we know that work done= force *distance moved
1. work done to push the book= 1.55*2.8=4.34J
2. Work against friction = force of friction x distance
= 0.34*2.8=0.952J
Step two:
the work done on the book is the net work, which is
Network done= work done to push the book- Work against friction
Network done= 4.32-0.952=3.36J
<u>Therefore the work of the 1.55N 3.36J</u>
Answer:
1.0125 x 10^19
Explanation:
current flowing through conductive wire= 9mA = 9 x 10^ -3 A
charge passing per 3 min
Q = It
= 9 x 10^ -3 x (3 x 60)
= 1.620 C
no of electrons in charge
Q = ne
1.620 = n x 1.6 x 10 ^ -19
n. = 1.0125 x 10 ^19
Answer:
what time does it start.
what do I need to join.
what are your expectations.
Answer:
Explanation:
The ratio of the weight of corn to the weight of water consumed will be the same. Either we compare the total weights for the total amount of corn or we compare only a small proportion of it. So, we consider the given 25 kg of corn. So, the mass of corn is given:
m₁ = mass of corn = 25 kg
Now, for mass of water, we will use its density:
ρ₂ = m₂/V₂
m₂ = ρ₂V₂
where,
m₂ = mass of water = ?
V₂ = Volume of water consumed by 25 kg corn = 20 m³
ρ₂ = density of water = 1000 kg/m³
Therefore,
m₂ = (1000 kg/m³)/(20 m³)
m₂ = 50 kg
Now, we calculate the ration:
