Answer:
Impulse in the first collision is greater
Explanation:
u = Initial velocity of cart
v = Final velocity of cart
m = Mass of of cart
First collision
Impulse
Second collision
Impulse
Hence, the impulse in the first collision is greater than the second impact
Answer:
A) mr = 100 kg
B) Fr = 210N
C) Ft = -199.5N
Explanation:
By conservation of the momentum:
mt*Vo = (mr + mt) * Vf Solving for mr:
mr = mt*Vo / Vf - mt = 100 kg
The average force on the receiver:
mr *(Vf - 0) = Fr * Δt Solving for Fr:
Fr = 210 N
The average force on the tackler:
mt * (Vf - Vo) = Ft * Δt Solving for Ft:
Ft = -199.5 N
Answer:
1. Our eye should be vertically abvove the point, where the measurement is to be taken.
2. For proper measurement, Keep the ruler exactly along the length , for the measurement
Explanation:
good luck
Answer:
Explanation:
Since work done is in the form of potential energy, we will use the formula of potential energy here.
We know that,
<h3>P.E. = mgh </h3>
Where,
m = mass = 20 kg
g = acceleration due to gravity = 10 m/s²
h = vertical height = 20 m
So,
<h3>Work done = mgh</h3>
Work done = (20)(10)(20)
Work done = 4000 joules
Work done = 4 kJ
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The Mass of the car = 782.1 Kg
<h3>What is the mass of the car?</h3>
The mass of the car is calculated as follows:
- Mass = Force/ acceleration
The force on the car = 6570 N
The acceleration of the car, a = 38 - 0/4.5
acceleration = 8.44 m/s²
Mass of the car = 6570/8.44
Mass of the car = 782.1 Kg
In conclusion, the mass of the car is obtained from the acceleration and force on the car.
Learn more about mass and acceleration at: brainly.com/question/19385703
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