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4 years ago

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A mass of gas under constant Pressure occupies a volume of 0.5 M3 At a temperature of 20ﾟC using the formula for Cubic expansion

What will be the volume at a temperature Of 45ﾟC without a change in pressure

1 answer:

MAVERICK [17]4 years ago

7 0

To answer this question, we must use the equation for the volumetric expansion of gases at constant pressure. This equation is given by:

$V=V_{0}(1 + \alpha(T_{2}-T_{1}))$

We know:

$V_{0}$ is the initial volume $= 0.5 m ^ 3$

ΔT is the temperature change = 45 ° -20 ° = 25 °

$\alpha$ is the coefficient of gas expansion and is equal to 1/273

Then the final volume of the gas is:

$V=0.5*(1+\frac{1}{273}*25)$

$V=0.546m^ 3$

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$-\mu_{k}(F sin \theta +mg)+Fcos \theta=0$

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$-\mu_{k}F sin \theta -\mu_{k}mg)+Fcos \theta=0$

we add $\mu_{k}mg$ to both sides so we get:

$-\mu_{k}F sin \theta +Fcos \theta=\mu_{k}mg$

Nos we factor F so we get:

$F(cos \theta-\mu_{k} sin \theta)=\mu_{k}mg$

and now we divide both sides of the equation into $(cos \theta-\mu_{k} sin \theta)$ so we get:

$F=\frac{\mu_{k}mg}{cos \theta-\mu_{k}sin \theta}$

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$f_{s}=\mu_{s}(F sin \theta +mg)$

and

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when substituting one into the other we get:

$F cos \theta=\mu_{s}(F sin \theta +mg)$

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