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Ber [7]
3 years ago
10

A mass of gas under constant Pressure occupies a volume of 0.5 M3 At a temperature of 20゚C using the formula for Cubic expansion

What will be the volume at a temperature Of 45゚C without a change in pressure
Physics
1 answer:
MAVERICK [17]3 years ago
7 0

To answer this question, we must use the equation for the volumetric expansion of gases at constant pressure. This equation is given by:

V=V_{0}(1 + \alpha(T_{2}-T_{1}))

We know:

V_{0} is the initial volume = 0.5 m ^ 3

ΔT is the temperature change = 45 ° -20 ° = 25 °

\alpha is the coefficient of gas expansion and is equal to 1/273

Then the final volume of the gas is:

V=0.5*(1+\frac{1}{273}*25)

V=0.546m^ 3

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Answer:

Zero

Explanation:

Two long parallel wires each carry the same current I in the same direction. The magnetic field in wire 1 is given by :

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Similarly, force acting in wire 1 is given by :

F_1=\dfrac{\mu_oI_1I_2 l}{2\pi r}According to third law of motion, the force acting in wire 1 will be in opposite direction to wire 2 as :

F_2=-F_1

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7 0
3 years ago
At a meeting of physics teacher in Montana, the teachers were asked to calculate where a flour sack would land if dropped from a
Harlamova29_29 [7]

At a distance of 469.2 m from the original point below the airplane.

Explanation:

First of all, we have to calculate the time it takes for the sack to reach the ground.

To do so, we just analyze its vertical motion, which is a free-fall motion, so we can use the suvat equation:

s=ut+\frac{1}{2}at^2

where, taking downward as positive direction:

s = 300 m is the vertical displacement

u = 0 is the initial vertical velocity

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a=g=9.8 m/s^2 is the acceleration of gravity

Solving for t, we find the it takes for the sack to reach the ground:

t=\sqrt{\frac{2s}{a}}=\sqrt{\frac{2(300)}{9.8}}=7.82 s

Now we analyze the horizontal motion. The horizontal velocity of the pack is constant (since there are no forces along the horizontal direction) and equal to the initial speed of the airplane, so:

v_x = 60 m/s

We also know the total time of flight,

t = 7.82 s

Therefore, we can find the horizontal distance travelled by the sack:

d=v_x t = (60)(7.82)=469.2 m

So, the sack will land 469.2 m from the original point below the airplane.

Learn more about free fall and projectile motion:

brainly.com/question/1748290

brainly.com/question/11042118

brainly.com/question/2455974

brainly.com/question/2607086

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#LearnwithBrainly

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Help with speed problems #1-3
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1. Each plot represents the meters traveled by both the Hare and the Tortoise over a certain period of time (minutes).

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3. The Hare in the first 5 minutes had a rapid fast advancement up to 40 meters. But for the 5-20 mins. period the Hare did not move at all. Its speed stayed at the same place. But towards the end 20-25 mins. marks the Hare started moving again. At the end the Hare at first had a rapid acceleration but stopped for a long time then it sped up briefly. 
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