That is meters per second, same as velocity.
Answer:
v₀ = 16.55 m/s
Explanation:
This motion of the ball can be modeled as a projectile motion with following data:
R = Range of Projectile = 27.5 m
θ = Launch Angle = 50°
g = acceleration due to gravity = 9.81 m/s²
v₀ = Initial Speed of Ball = ?
Therefore, using formula for range of projectile, we have:

<u>v₀ = 16.55 m/s</u>
A. a tsunami
(if the earthquake is hitting the ocean, the water will get effected)
Answer:

Explanation:
<u>Motion With Constant Acceleration
</u>
It's a type of motion in which the velocity of an object changes uniformly over time.
The equation that describes the change of velocities is:

Where:
a = acceleration
vo = initial speed
vf = final speed
t = time
Solving the equation for a:

The ball starts at rest (vo=0) and rolls down an inclined plane that makes it reach a speed of vf=7.5 m/s in t=3 seconds.
The acceleration is:


Answer:
Range of wavelength will be
to 
Explanation:
We have given range of frequency is 400-560 Hz
Speed of the light 
We have to find the range of the wavelength of signal transmitted
Ween know that velocity is given by
, here
is wavelength and f is frequency
So for 400 Hz frequency wavelength will be 
And wavelength for frequency 560 Hz 
So range of wavelength will be
to 