Complete Question
A 95 kg clock initially at rest on a horizontal floor requires a 650 N horizontal force to set it in motion. After the clock is in motion, a horizontal force of 560 N keeps it moving with a constant velocity. Find the coefficient of static friction and the coefficient of kinetic friction.
Answer:
The value for static friction is
The value for static friction is
Explanation:
From the question we are told that
The mass of the clock is
The first horizontal force is
The second horizontal force is
Generally the static frictional force is equal to the first horizontal force
So
=>
=>
Generally the kinetic frictional force is equal to the second horizontal force
So
The s<span>tatic charges that are applied to neutral objects by friction, induction or conduction main utilise the creation of electrons or electric charges. Electrons flow forming a current into a specific medium known as a conductor which is mainly due to a significant potential difference between two points.</span>
Answer:
I = 16amp
Explanation:
Charge coulomb ( Q ) = It
Where I =current in ampere
t = time = 5 seconds
80 = I × 5
I = 80/5
I = 16amp
The current through the circuit will be I = 16amp
The second ball should strike at double the original t value
Answer:
w=fx
w=(15)(5)
w=75
the angle between the deplacement and N is 0