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KATRIN_1 [288]
3 years ago
5

What is the most likely effect of an increase in precipitation?

Physics
2 answers:
Vitek1552 [10]3 years ago
4 0
I'm thinking  the answer would be D.

I hope this helps ☺ Let me know if you have any others
kumpel [21]3 years ago
3 0
The answer is Fall in air temperture
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During a baseball game, a batter hits a high pop-up. If the ball remains in the air for 4.02 s, how high above the point where i
alukav5142 [94]

Answer:

d = 19.796m

Explanation:

Since the ball is in the air for 4.02 seconds, the ball should reach the maximum point from the ground in half the total time, therefore, t=2.01s to reach maximum height. At the maximum height, the velocity in the y-direction is 0.

So we know t=2.01, vi=0, g=a=9.8m/s and we are solving for d.

Next, you look for a kinematic equation that has these parameters and the one you should choose is:

d=vt+\frac{1}{2}at^2

Now by substituting values in, we get

d=(0\frac{m}{s})*(2.01s)+\frac{1}{2}(9.8\frac{m}{s^2})(2.01)^2

d = 19.796m

7 0
3 years ago
Suppose you have an object tied to a rope and are rotating it over your head in uniform circular motion. What would have to do t
Crazy boy [7]

Answer:

We must duplicate the length of the rope (R'=2R) to get

F'=\frac{1}{2}F

Explanation:

The equation of the centripetal force is given by:

F_{c}=ma_{c}

F_{c}=m\frac{v^{2}}{R}

Where:

R is the length of the rope

m is the mass of the object

v is the speed of the object

If we want to reduce the centripetal force in half, we can duplicate the length of the rope (R'=2R), which means:

F'_{c}=m\frac{v^{2}}{R'}

F'_{c}=m\frac{v^{2}}{2R}

F'_{c}=\frac{1}{2}F_{c}

I hope it helps you!

6 0
3 years ago
The pressure of liquid varies as per it's depth.
irga5000 [103]

Answer: The pressure in a liquid is different at different depths. Pressure increases as the depth increases. The pressure in a liquid is due to the weight of the column of water above. The greater pressure at the bottom would give a greater 'force per unit area' on the wall.

Explanation:

6 0
3 years ago
An object moves with simple harmonic motion. If the amplitude and the period are both doubled, the object's maximum speed is 1.
Kisachek [45]

Answer:

The object's maximum speed remains unchanged.

Explanation:

The speed of a particle in SHM is given by :

v(t)=A\omega\ sin(\omega t)

Maximum speed is, v_{max}=A\omega

If A' = 2A and T' = 2T

v'_{max}=(2A)\dfrac{2\pi}{2T}

v'_{max}=(A)\dfrac{2\pi}{T}

v'_{max}=v_{max}

So, the maximum speed of the object remains the same i.e. it remains unchanged. Hence, this is the required solution.

6 0
3 years ago
How should Delana figure out how much power is needed to do 462 joules of work in 9.61 seconds?
Lostsunrise [7]

Answer: 48.08 watts

Explanation:

power needed = ?

Work done = 462 joules

Time taken = 9.61 seconds

Recall that power is the rate of energy expended or workdone per unit time. i.e Power = Workdone / Time

Power = 462 joules / 9.61 seconds

Power = 48.08 watts

Thus, 48.08 watts of power is needed to the work.

7 0
4 years ago
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