If a group of workers can apply a force of 1,275 newtons to move a crate 26 meters, what amount of work will they have accomplis
1 answer:
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Answer:
Explanation:
To express the cheetah's top speed in miles per hour, we just need to find the conversion factor.
We know that the top speed is
So, we want to obtain miles from meters and hours from seconds.
<h3>miles from meters</h3>First we write the equivalence:
Now, we can divide by 1609.34 meters on both sides:
The left sides equals 1, so
And this is our conversion factor from meters to miles. Now, we can multiply our top speed by this conversion factor, as the conversion factor equals one, and is dimensionless, the physical meaning will be the same.
This is the top speed in miles per second, now, for obtaining miles per hour:
<h3>hours from seconds</h3>We can do pretty much the same, first, the equivalence:
as the seconds are dividing in the velocity, we know divide by 1 hour.
and know we just multiply our top speed by this conversion factor
Answer:
m1/6 ( c )
Explanation:
since all the balls starts having the same momentum after the two collisions we will apply the principal of conservation of energy
After first collision
m1v = m1v1 + m2v2 --- ( 1 )
After second collision
m2v2 = m2v2 + m3v3 ---- ( 2 )
combining equations 1 and 2
m1v = m1v1 + m2v2 + m3v3 ----- ( 3 )
All balls moving at the same momentum ( p ) = m1v1 = m2v2 = m3v3
note ; 3p = m1v ∴ m3 = ----- ( 4 )
applying conservation of energy
3v = v1 + v2 + v3 ------- ( 5 )
also 3m1v1 = m1v = v1 = v/3 =
v2 + v3 = 8/3 v ----- ( 6 )
next eliminate V3 for equation 6 by applying conservation of energy and momentum
m1 = 2m2 ------ ( 7 )
now using p1 = p2 = m1v1 = 1/2 m1v1 hence v2 = 2v1 where v1 = 1/3 v
hence ; v2 = 2/3 v ------- ( 8 )
solving with equation 6 and 8
v3 = 2v ------ ( 9 ) ∴ v/v3 = 1/2 ---- ( 10 )
solving with equation 9 and 10
m3 = m1/3 * 1/2 = m1/6