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Iteru [2.4K]
3 years ago
15

A typical meteor that hits the earth's upper atmosphere has a mass of only 2.5 g, about the same as a penny, but it is moving at

an impressive 40 km/s. As the meteor slows, the resulting thermal energy makes a glowing streak across the sky, a shooting star. The small mass packs a surprising punch.
At what speed would a 900 kg compact car need to move to have the same kinetic energy?
Physics
1 answer:
attashe74 [19]3 years ago
8 0

Answer:

Answer:u=66.67 m/s

Explanation:

Given

mass of meteor m=2.5 gm\approx 2.5\times 10^{-3} kg

velocity of meteor v=40km/s \approx 40000 m/s

Kinetic Energy of Meteor

K.E.=\frac{mv^2}{2}

K.E.=\frac{2.5\times 10^{-3}\times (4000)^2}{2}

K.E.=2\times 10^6 J

Kinetic Energy of Car

=\frac{1}{2}\times Mu^2

=\frac{1}{2}\times 900\times u^2

\frac{1}{2}\times 900\times u^2=2\times 10^6  

900\times u^2=4\times 10^6

u^2=\frac{4}{9}\times 10^4

u=\frac{2}{3}\times 10^2

u=66.67 m/s

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A rocket with a mass of 2.0 Ã 106 kg is designed to take off from the surface of the earth by burning fuel and ejecting it with
julsineya [31]

thrust force getting from the burning of mass should balance the weight of the rocket

here thrust force is given as

F_t = v\frac{dm}{dt}

now by force balance we can say

mg = v \frac{dm}{dt}

now plug in all values in this

(2 \times 10^6)(9.8) = 3500 \times \frac{dm}{dt}

\frac{dm}{dt} = \frac{19.6 \times 10^6}{3500}

\frac{dm}{dt} = 5600 kg/s

so rate of mass burning per second will be 5600 kg per second in order to lift up the rocket

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3 years ago
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wlad13 [49]

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3 years ago
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solong [7]

Answer:

1) A trait is a specific feature or characteristic, typically genetic.

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What are the component parts of modern fireworks? What does each part do?
EleoNora [17]

Answer: Aluminum, Antimony, Barium, Calcium, Carbon, Chlorine, Copper, Iron, Lithium, Magnesium, Oxygen, Zinc, Titanium, Strontium, Sulfur, Sodium, Potassium, Phosphorus

Explanation:

Aluminum: Aluminum is a common component of sparklers.  It is used to produce silver and white flames and sparks.

Antimony: Antimony is used to create firework glitter effects.

Barium: Barium is used to create green colors in fireworks, and it can also help stabilize other volatile elements.

Calcium: Calcium is used to deepen firework colors. Calcium salts produce orange shades in the fireworks.

Carbon: Carbon is an important components of black powder, which is used as a propellant in fireworks. Carbon provides the fuel for a firework. Common forms include carbon black, sugar, or starch.

Chlorine: Chlorine is an important component of many oxidizers in fireworks. Several of the metal salts that produce colors contain chlorine.

Copper: Copper compounds produce blue shades in fireworks.

Iron: Iron is used to produce sparks. The heat of the metal determines the color of the sparks in this case.

Lithium: Lithium is a metal that is used to impart a red color to fireworks. Lithium carbonate, in particular, is a common colorant.

Magnesium: Magnesium burns a very bright white, so it is used to add white sparks or improve the overall brilliance of a firework.

Oxygen: Fireworks include oxidizers, which are substances that produce oxygen in order to support. The oxidizers are usually nitrates, chlorates, or perchlorates. Sometimes the same substance is used to provide oxygen and color.

Phosphorus: Phosphorus burns spontaneously in air and is also responsible for some glow-in-the-dark effects. It may be a component of a firework's fuel.

Potassium: Potassium helps to oxidize firework mixtures. Potassium nitrate, potassium chlorate, and potassium perchlorate are all important oxidizers.

Sodium: Sodium produces a gold or yellow color in fireworks, however, the color may be so bright that it masks less intense colors.

Sulfur: Sulfur is a component of black powder. It is found in the firework's propellant/fuel.

Strontium: Strontium salts give a red color to fireworks. Strontium compounds are also important for stabilizing fireworks mixtures.

Titanium: Titanium metal can be burnt as powder or flakes to produce silver sparks.

Zinc: Zinc is used to create smoke effects in fireworks and other pyrotechnic devices.

5 0
4 years ago
La distancia por carretera de Chitré a Parita es de 12 km; exprese en pies ésta distanciaLa distancia por carretera de Chitré a
densk [106]

Answer:

La distancia por carretera de Chitré a Parita es de 12 km o 39370.08 pies.

Explanation:

La regla de tres es una forma de resolver problemas de proporcionalidad entre tres valores conocidos y un valor desconocido, estableciendo una relación de proporcionalidad entre todos ellos.

Si la relación entre las magnitudes es directa, es decir, cuando una magnitud aumenta, también lo hace la otra (o cuando una magnitud disminuye, también lo hace la otra), se debe aplicar la regla directa de tres. Para resolver una regla directa de tres, se debe seguir la siguiente fórmula, siendo a, b y c los valores conocidos y x el valor a determinar:

a ⇒ b

c ⇒ x

Entonces x=\frac{c*b}{a}

La regla directa de tres es la regla que se aplica en este caso donde hay un cambio de unidades. Para realizar esta conversión de unidades, primero debes saber que 1 km = 3280,84 pies. Entonces, si 1 km son 3280,84 pies, ¿cuántos pies son 12 km?

1 km ⇒ 3280.84 pies

12 km ⇒ x

x=\frac{12 km*3280.84 pies}{1 km}

x= 39370.08 pies

<u><em>La distancia por carretera de Chitré a Parita es de 12 km o 39370.08 pies.</em></u>

7 0
3 years ago
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