The amplitude and wavelength are measured in meters while frequency is measured in decibels.
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Units of measurement:</h2>
- Amplitude: It is the maximum displacement of the points of the wave from its mean position. Hence it is measured in meters.
- Frequency: It is measured in Hertz. A hertz is a number of waves passed from a single point per second.
- Wavelength: It is the distance between two consecutive crests or troughs. hence it is measured in meters.
- Wave speed: It is measured in m/s.
- Loudness: The loudness of the sound is measured in decibels.
Therefore, the amplitude and wavelength are measured in meters while frequency is measured in decibels.
Learn more about decibels:
brainly.com/question/1851849
Answer:
1, 1583.33 V/m
2, 4.72*10^-12 C
3, 39.2*10^-11 C
Explanation:
1
E = V / d
E = 8.55 / 5.4*10^-3
E = 8.55 / 0.0054
E = 1583.33 V/m
2
Capacitance, C = (k * e0 * A) / d, where k = 1
A = area of capacitor, 3.37 cm² = 3.37*10^-4 m²
d = plate separation, 5.4 mm
e0 = Constant, 8.85*10^-12
Applying these, we have
C = (1 * 8.85*10^-12 * 3.37*10^-4) / 5.4*10^-3
C = 29.82*10^-16 / 0.0054
C = 5.52*10^-13 F
Since Q = CV, then
Q = 5.52*10^-13 * 8.55
Q = 4.72*10^-12 C
3
We are given that k = 83, so
Capacitance, C = (k * e0 * A) / d
C = (83 * 8.85*10^-12 * 3.37*10^-4) / 5.4*10^-3
C = 2.475*10^-13 / 0.0054
C = 4.58*10^-11 F
Q = CV
Q = 4.58*10^-11 * 8.55
Q = 39.2*10^-11 C
Answer:
i hope it help
Explanation:
It's possible to step 12 volts down to 6 volts by incorporating a pair of 10,000-ohm resistors into the circuit. Cut two lengths of wire, and strip each wire of 1/2 inch of insulation at each end. Attach one end of the first wire to the positive terminal on the power supply.