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3 years ago

HELP A.S.A.P SCIENCE

Physics

2 answers:

Nimfa-mama [501]3 years ago

8 0

I think its d, it is pointing to the whole circle which prob rlly makes it a proton

Mashutka [201]3 years ago

6 0

Answer:

The answer is actually C

Explanation:

An atom consists essentially of three types of particles:

- Protons: these are contained in the nucleus, and they are positively charged

- Neutrons: this are also contained in the nucleus, but they have no electric charge

- Electrons: they orbit around the nucleus, and they have negative charge

Based on this diagram, we see that the particle labeled by C is a proton, since it is in the nucleus and it is positively charged. The particle labeled by B is a neutron, while the particle labeled by A is an electron.

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if you have 34 pounds of meat at 200F and you immerse it in 15 liters of water at 25C what is the final temp of the water? ( spe

hram777 [196]

Answer:

The specific heat capacity is the heat or energy required to change one unit mass of a substance of a constant volume by 1 °C. The formula is Cv = Q / (ΔT ⨉ m)

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2 years ago

a flag of mass 2.5 kg is supported by a single rope. A strong horizontal wind exerts a force of 12 N on the flag. Calculate the

tatuchka [14]

The free-body diagram of the forces acting on the flag is in the picture in attachment.

We have: the weight, downward, with magnitude
$W=mg = (2.5 kg)(9.81 m/s^2)=24.5 N$
the force of the wind F, acting horizontally, with intensity
$F=12 N$
and the tension T of the rope. To write the conditions of equilibrium, we must decompose T on both x- and y-axis (x-axis is taken horizontally whil y-axis is taken vertically):
$T \cos \alpha -F=0$
$T \sin \alpha -W=$
By dividing the second equation by the first one, we get
$\tan \alpha = \frac{W}{F}= \frac{24.5 N}{12 N}=2.04$
From which we find
$\alpha = 63.8 ^{\circ}$
which is the angle of the rope with respect to the horizontal.

By replacing this value into the first equation, we can also find the tension of the rope:
$T= \frac{F}{\cos \alpha}= \frac{12 N}{\cos 63.8^{\circ}}=27.2 N$

7 0

3 years ago

Two equipotential surfaces surround a +3.10 x 10-8-c point charge. how far is the 290-v surface from the 41.0-v surface?

MrMuchimi

T<span>he equation to be used here to determine the distance between two equipotential points is:
V = k * Q / r

where v is the voltage of the point, k is a constant, Q is charge of the point measured in coloumbs and r is the distance.
In this case, we can use ratio of proportions to determine the distance between the two points. in this respect,

Point 1:
V = k * Q / r = 290
r = k*Q/290 ; kQ = 290r

Point 2:
V = k * Q / R = 41
R = k*Q/41
from equation 10 kQ = 290r
R = 290/(41)= 7.07 m
The distance between the two points then is equal to 7.07 m.

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2 years ago

A 20 kg bike accelerates at 10 m/s2. What was the force?

agasfer [191]

Answer:

200 N = 200 Newtons

Explanation:

Just use the formula F = m*a

F = Force in Newtons

m = mass and is 20 kg

a = acceleration and is 10 m/s^2

F = 20 * 10

F = 200 Newtons.

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2 years ago

Your science teacher gives you three liquids to pour into a jar. After pouring, the liquids layer as seen here. What property of

Blizzard [7]

A. mass
b. color
c. density
d. texture

i believe A

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2 years ago

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