B is the answer, I’m really good at this subject
Answer:
80 angle of incidence=angle of reflection
Explanation:
The answer is
Pitch of the buzzer increased (higher tone) as it moves towards the observer
Answer:
a ,b , d ,e
Explanation:
took the k12 quiz and got a 100
Answer:

Explanation:
Given that
Length = L
At initial over hanging length = Xo
Lets take the length =X after time t
The velocity of length will become V
Now by energy conservation

So

We know that



At t= 0 ,X=Xo
So we can say that

So the length of cable after time t
