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m_a_m_a [10]
3 years ago
8

an object I placed in front of the of focal length 20 cm what is the nature of image formed of the object distance is 50 cm.​

Physics
1 answer:
stiks02 [169]3 years ago
4 0

Answer:

Focal length f=−20 cm

Object distance u=−50 cm

Using

v

1

−

u

1

=

f

1

Or

v

1

−

(−50)

1

=

−20

1

We get v=−14.3 cm

Since, v is negative. So image formed is virtual.

Hence, virtual image is formed at a distance of 14.3 cm in front of the lens.

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Solnce55 [7]

Answer:

size get smaller maybe there is no object remaining

3 0
3 years ago
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An elevator cable breaks when a 925-kg elevator is 28.5 m above the top of a huge spring Ak = 8.00 * 104 N????mB at the bottom o
rosijanka [135]

Answer:

a) = 258352.5J

b) = 23.63 m/s

c) = 1.8m

Explanation:

Data;

Mass = 925kg

Distance (s) = 28.5m

Force constant (k) = 8.0*10⁴ N/m

g = 9.8 m/s²

a) = work = force * distance

But force = mass * acceleration

Force = 925 * 9.8 = 9065N

Work = F * s = 9065 * 28.5 = 258352.5J

b) acceleration (a) = (v² - u²) / 2s

a = v² / 2s

v² = a * 2s

v² = 9.8 * (2 * 28.5)

v² = 9.8 * 57

v² = 558.6

v = √(558.6)

V = 23.63 m/s

C). The work stops when the work done to raise the spring equals the work done to stop it by the spring

W = ½kx²

258352.5 = ½ * 8.0*10⁴ * x²

(2 * 258352.5) = 8.0*10⁴x²

516705 = 8.0*10⁴x²

X² = 516705 / 8.0*10⁴

X² = 6.46

X = √(6.46)

X = 2.54m

The compression was about 2.54m

3 0
3 years ago
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A train of mass 5.6 × 10^5kg is at rest in a station.at time t=0s, a resultant force acts on the train and it starts to accelera
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Answer:

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Explanation:

Given parameters:

Mass of the train  = 5.6 x 10⁵kg

Acceleration  = 0.75m/s²

Unknown:

Resultant force = ?

Solution:

According to newton's second law, force is the product of mass and acceleration;

   Force  = mass x acceleration

Resultant force that acts on the train is given below;

 Force  = 5.6 x 10⁵kg  x 0.75m/s²  = 420000N

7 0
3 years ago
Let the displacement function of a particle is x(t)=(20t^2-15t+200). Find the total displacement, instantaneous velocity and ins
irga5000 [103]

Answer:

A.) 39.5 m

B.) 0

C.) 60m/s^2

Explanation:

Given that a displacement function of a particle is x(t)=(20t^2-15t+200).

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Reduce everything by dividing them by 5

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For instantaneous velocity, differentiate x(t). That is,

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If dy/dt = 0, then

60t - 15 = 0

60t = 15

t = 15/60

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Substitutes t in equation (1)

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V = 60 (0.25) - 15

V = 0.

and to find instantaneous acceleration, differentiate dv/dt

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Therefore, acceleration = 60 m/s^2

4 0
2 years ago
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I think the answer is c
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3 years ago
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