Among the choices above the best describe the next step that a student would to after gathering of data, collecting of data and form graphs is to analyze and conclude all the data that information that has been collected. Thank you for posting your question here. I hope it helps.
A)After 3,5s -->v=v0+gt=21+(-9,8•3,5)=21+(-34,3)=-13,3m/s;
b)The maximum height that the orange reaches is h max=v0^2/2g=22,5m;v^2=sqrt(2gh)=>h=v^2/2g=9,025m.The height of the orange is H=h max-h=13,475m.;
c)The orange is traveling down.
We can ignore all that business about resting on the rock and
rolling down part of the way and then resting on the moss.
Its potential energy right now doesn't depend on what happened
to it yesterday. We don't care.
All we care about is that we're walking along in the park and we
notice a 1.5kg rock lying in moss 10 meters above the ground.
Gravitational potential energy
= (mass) · (gravity) · (height)
= (1.5 kg) · (9.8 N/kg) · (10 m)
= 147 (kg · N · m / kg)
= 147 joules
Using the wavelength expressions, such as the distance between two peaks of a wave, that of the frequency as a function of the speed and the wavelength, such as the period inversely proportional to the frequency we have to for the first question
the wavelength is the distance between the two ridges that is
![\lambda = 0.8m](https://tex.z-dn.net/?f=%5Clambda%20%3D%200.8m)
For the second question the frequency is determined as the rate of change of the velocity versus the wavelength, that is
![f = \frac{v}{\lambda}](https://tex.z-dn.net/?f=f%20%3D%20%5Cfrac%7Bv%7D%7B%5Clambda%7D)
![f = \frac{2.2}{0.8}](https://tex.z-dn.net/?f=f%20%3D%20%5Cfrac%7B2.2%7D%7B0.8%7D)
![f= 2.75Hz \approx 2.8Hz](https://tex.z-dn.net/?f=f%3D%202.75Hz%20%5Capprox%202.8Hz)
For the third question the period is inversely proportional to the frequency, therefore
![T = \frac{1}{f}](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7B1%7D%7Bf%7D)
![T = \frac{1}{2.8}](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7B1%7D%7B2.8%7D)
![T = 0.36s](https://tex.z-dn.net/?f=T%20%3D%200.36s)
Answer:
Explanation:
separation between slit d = 1.2 x 10⁻⁴ m
distance of screed D = 3.5 m
distance of second order right fringe
= 2λD / d where λ is wavelength of light .
2λD / d = .0375
2 x λ x 3.5 / 1.2 x 10⁻⁴ = .0375
λ = 6428 x 10⁻¹⁰ m
= 643 nm .