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mr_godi [17]
4 years ago
5

Which item is made from a basic ingredient? Soap Tea Wine Vinegar

Chemistry
2 answers:
viva [34]4 years ago
8 0

Answer is: soap.

Soap is a salt of a fatty acid and alkaline (basic) solution.  An alkaline solution induces saponification of triglyceride fats into salts of fatty acids.

Toilet soap has sodium and potassim cations.  Metallic soap have magnesium and calcium cations.

Sodium soaps, made from sodium hydroxide are firm and potassium soaps, made from potassium hydroxide, are softer or often liquid.

german4 years ago
6 0

THE answer to your Question is TEA

<u><em>HOPE THIS HELPED</em></u> !! ; )

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HELP ASAP!! DUE TOMORROW!! WILL MARK AS BRAINLIEST IF ANSWERED IN THE NEXT HOUR!!
fgiga [73]
2. Left to right (smallest to largest) F-, Mg2+, Na+, and K+

5. Cs, Ga, As, N, O

6. Cs or H (probably cesium)

7. In or In 2+ (not sure which)

Hope this helps, I've never really seen questions like this before.
3 0
4 years ago
Na3PO4 + AlBr3 ----&gt; ?
Sati [7]
Na₃PO₄(aq)+AlBr₃(aq)→3NaBr(aq)+AlPO₄(s)

This is a double replacement reaction.  You can tell that there has to be 3NaBr molecules since there are 3 Na atoms in sodium phosphate and 3 Br atoms in aluminum bromide.  We also know that Na has an oxidation number of +1 which means PO₄ needs to have an oxidation number of -3 while Br has an oxidation number of -1 which means Al has an oxidation number of +3.  That means that Al³⁺ and PO₄³⁻ can from AlPO₄  
I hope this helps.  Let me know if anything is unclear.
8 0
4 years ago
which of these pieces of equipment would be the most appropriate for precisely measuring 29 mL of liquid? Explain your reasoning
Anna007 [38]

Answer:

The best equipment would be the graduated cylinder. Why?

Firstly, the smallest marking on the graduated cylinder is 2 mL, while on all the others the smallest marking is way above that, like 25 mL and 100 mL.

Without even going into the details, we can first rule out the volumetric flask, since its smallest marking is 100 mL and even that is already bigger than our sample size, hence we would have no markings to accurately measure out 29 mL of our sample had we used the volumetric flask.

Next to be ruled out would be the Erlenmeyer flask, as you can see in the image, it only has three marking, and as the smallest marking is 25 mL, each marking is at least 25 mL, and even so far as going up to 50 mL. This cannot let us accurately measure 29 mL out at all, due to the markings being way too big to do that. Hence, the Erlenmeyer flask is ruled out.

Finally, the beaker seems to be a worthy candidate! Unfortunately, for the same reason as the Erlenmeyer flask, as you can see in the image each marking represents 10 mL. We cannot measure 9 mL in the beaker accurately, and hence the beaker is ruled too.

We are left with the graduated cylinder, and that is our answer.

Explanation:

Hope this helped!

5 0
3 years ago
Calculate Delta G for each reaction using Delta Gf values: answer kJ ...thank you
Leni [432]

Answer:

a) \Delta G=2.6kJ

b) \Delta G=-979.57kJ

c) \Delta G=264.21kJ

Explanation:

Hello,

In this case, in each reaction we must subtract the Gibbs free energy of formation the reactants to the Gibbs free energy of formation of the products considering each species stoichiometric coefficients. In such a way, the Gibbs free energy of formations are:

\Delta _fG_{H_2}=\Delta _fG_{I_2}=0kJ/mol\\\Delta _fG_{HI}=1.3kJ/mol\\\Delta _fG_{CO_2}=-394.4kJ/mol\\\Delta _fG_{CO}=-137.3 kJ/mol\\\Delta _fG_{NH_3}=16.7 kJ/mol\\\Delta _fG_{HCl}=-95.3kJ/mol\\\Delta _fG_{MnO_2}=465.37kJ/mol\\\Delta _fG_{Mn}=0kJ/mol\\\Delta _fG_{NH_4Cl}=-342.81kJ/mol

So we proceed as follows:

a)

\Delta G=2\Delta _fG_{HI}-\Delta _fG_{H_2}-\Delta _fG_{I_2}\\\\\Delta G=2*1.3\\\\\Delta G=2.6kJ

b)

\Delta G=\Delta _fG_{Mn}+2*\Delta _fG_{CO_2}-\Delta _fG_{MnO_2}-2*\Delta _fG_{CO}\\\\\Delta G=0+2*-394.4-465.37-2*-137.3\\\\\Delta G=-979.57kJ

c)

\Delta G=\Delta _fG_{NH_3}+\Delta _fG_{HCl}-\Delta _fG_{NH_4Cl}\\\\\Delta G=16.7-95.3-(-342.81)\\\\\Delta G=264.21kJ

Regards.

6 0
3 years ago
How many dekagrams are in a kilogram​
Norma-Jean [14]

Answer:

1=100 1 Kilogram (kg) is equal to 100 dekagrams (dag). To convert kilograms to dekagrams, multiply the kilogram value by 100.

Explanation:

3 0
1 year ago
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