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RideAnS [48]
3 years ago
5

A pilot wants to fly on a bearing of 74.9 degrees. By flying due east, he find s that a 42-mph wind, blowin from the south, puts

him on course. Find the airspeed and the groundspeed.
Physics
1 answer:
hichkok12 [17]3 years ago
3 0
The bearing shows the angle from north to the line (c), you want to see the angle inside the triangle so that will be 90-[bearing]. 

<span>a=42 (42 mph wind blowing north) </span>

<span>A= 90-74.9 </span>
<span>A= 15.1 degrees </span>

<span>Ground speed is the speed the plane is going including the wind. </span>
<span>ground speed = c </span>
<span>Airspeed = b </span>

<span>You have the angle, and you have the "Opposite" and want to find the "Hypotenuse". </span>
<span>SOH CAH TOA </span>

<span>Sin x = Opp/Hypot </span>

<span>Sin(15.1) = 42/c </span>
<span>c = 42/Sin(15.1) </span>
<span>c = 161.53 </span>

<span>Ground speed of the plane is 161.53 mph </span>

<span>Airspeed = b </span>

<span>Tan x = Opp/Adj </span>
<span>Tan (15.1) = 42/b </span>
<span>b = 42/Tan(15.1) </span>
<span>b = 161.53 </span>

<span>Airspeed = 161.53 mph </span>

<span>(so the answer is ground speed of 161.53mph)</span>
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Skater 1 has a mass of 105.0 kg and a velocity of 2.0 m/s to the left. He
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The final velocity of skater 1 is 3.7 m/s to the right. The right option is O A. 3.7 m/s to the right.

<h3>What is velocity?</h3>

Velocity can be defined as the ratio of the displacement and time of a body.

To calculate the final velocity of Skater 1 we use the formula below.

Formula:

  • mu+MU = mv+MV............ Equation 1

Where:

  • m = mass of the first skater
  • M = mass of the second skater
  • u = initial velocity of the first skater
  • U = initial velocity of the second skater
  • v = final velocity of the first skater
  • V = final velocity of the second skater.

make v the subject of the equation.

  • v = (mu+MU-MV)/m................ Equation 2

Note: Let left direction represent negative and right direction represent positive.

From the question,

Given:

  • m = 105 kg
  • u = -2 m/s
  • M = 71 kg
  • U = 5 m/s
  • V = -3.4 m/s.

Substitute these values into equation 2

  • v = [(105×(-2))+(71×5)-(71×(-3.4))]/105
  • v = (-210+355+241.4)/105
  • v = 386.4/105
  • v = 3.68 m/s
  • v ≈ 3.7 m/s

Hence, the final velocity of skater 1 is 3.7 m/s to the right. The right option is O A. 3.7 m/s to the right.

Learn more about velocity here: brainly.com/question/25749514

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