Which of the following describes an action-reaction pair?

A model train traveling at a constant speed around a circular track has a constant velocity

Mrac [35]

The answer should be yes

7 0

3 years ago

Read 2 more answers

A ball is throw into the sky at 18m/s. How high can it reach?

Komok [63]

Answer:

The maximum height of the ball will be "16.53 m".

Explanation:

Given that,

$V_{final} = 18 \ m/s$

As we know,

The initial as well the final height on the ball will be same after it reaches it's maximum height.

then,

⇒ $V_{final}=V_{initial}$

where, $V_{initial} = \sqrt{2gh}$

$=\sqrt{2\times 9.8\times h}$

$=\sqrt{19.6h}$

hence,

The max height of the ball will be:

⇒ $18=\sqrt{19.6h}$

$19.6h=324$

$h=\frac{324}{19.6}$

$=16.53 \ m$

8 0

3 years ago

Chloe is playing the flute some distance away from a crowd. If the atmospheric temperature is 15°C, what is the speed of the sou

jok3333 [9.3K]

The solution to your problem is as follows:

speed of sound = 331.4 + 0.61 x T
speed of sound = 331.4 + 0.61 x 15
speed of sound = 331.4 + 9.15
<span>speed of sound = 340.55 m/s
</span>
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

5 0

4 years ago

Why do you think the objects in each collision experience a different change in velocity?

Sphinxa [80]

Answer:

In a collision, there is a collision force which endures for some amount of time to cause an impulse. This impulse acts upon the object to change its velocity and thus its momentum

8 0

3 years ago

Consider a machine of mass 70 kg mounted to ground through an isolation system of total stiffness 30,000 N>m, with a measured

kvv77 [185]

Answer:

a)0.0229 m

b)0.393 rad

c)1.57

d)707.6 N

e)0.298 m/s

Explanation:

Given:

Mass of the machine, m=70 kg
Stiffness of the system, k=30000 N/m
Damping ratio=0.2
Damping force, F=450 N
Angular velocity $\omega=13\ \rm rad/s$

a)We know that the amplitude X at steady state is given by

$X=\dfrac{\dfrac{F_0}{m}}{\sqrt{\omega_n^2-\omega^2)^2 +(2\rho \omega_n\omega)^2}}\\$

Where

$\omega_n=\sqrt{\dfrac{k}{m}}\\\\=\sqrt{\dfrac{30000}{70}}\\\\=20.7\ \rm rad/s$

$\omega=13\ \rm rad/s$
$\rho=0.2$

$F_0=450\ \rm N$
$m=70\ \rm kg$

$X=\dfrac{\dfrac{450}{70}}{\sqrt{20.7^2-13^2)^2 +(2\times 0.2\times20.7\times13)^2}}\\[tex]X=0.0229\ \rm m$

b) The phase shift of the motion is given by

$\tan\phi=\dfrac{2\rho \omega_n \omega }{\omega_n^2-\omega^2}\\\\\dfrac{2\times0.2\times20.7\times13 }{20.7^2-\13^2}\\\\\phai=0.393\\$

c)Transmissibility ratio is given by

$T.R.=\sqrt{\dfrac{1+(2\rho r)^2}{(1-r^2)^2+{(2\rho r)^2}}}\\\\T.R.=\sqrt{\dfrac{1+(2\times0.2\times0.628)^2}{(1-0.628^2)^2+{(2\times0.2\times0/628)^2}}}\\\\=1.57$

d)The magnitude of the force transmitted to the ground is

$F_T=(T.R)\times F_0\\\\=450\times1.57\\\\=707.6\ \rm N$

e)The maximum velocity is given by $V_{max}$

$V_{max}=\omega A_0\\\\=13\times 0.0229\\\\=0.298\ \rm m/s$

6 0

3 years ago