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Airida [17]
3 years ago
9

Nitrogen has a density of 1.17 x 10^-3 g/cm^3. If you have 2,500 cm^3 of nitrogen gas, which of the following is the correct mas

s of nitrogen, using significant figures?
A. 2.92 g

B. 2.2 x 10^6g

C. 14 x 10^6g

D. 2.9 g
Chemistry
2 answers:
ELEN [110]3 years ago
8 0
I think the correct answer from the choices listed above is option D. The correct mass of nitrogen would be 2.9 g. The mass is calculated by multiplying the density and the volume of the substance. The correct answer should have two significant figures since it is the least precise operation.
8090 [49]3 years ago
7 0

Answer : The correct option is, (A) 2.92 g

Explanation :

Density : It is defined as the mass of a substance contained per unit volume.

Formula used :

Density=\frac{Mass}{Volume}

Given :

Density of nitrogen gas = 1.17\times 10^{-3}g/cm^3

Volume of nitrogen gas = 2500cm^3

Now we have to determine the mass of nitrogen gas.

By using formula, we get:

1.17\times 10^{-3}g/cm^3=\frac{Mass}{2500cm^3}

Mass=2.92g

The rule apply for the multiplication and division is :

The least number of significant figures in any number of the problem determines the number of significant figures in the answer.

In this problem, the least number of significant figures is 3. So, the answer will be in 3 significant figures.

Therefore, the mass of nitrogen gas is 2.92 grams

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3 years ago
A chemist needs to make 250 mL of a 2.50 M aqueous solution of ammonium hydroxide from a 6.00 M ammonium hydroxide solution. How
Furkat [3]

Answer:

250 mL (total solution)  = 104 mL (stock solution)  + 146 mL (water)

Explanation:

Data Given

M1 = 6.00 M

M2 = 2.5 M

V1 = 250 mL

V2 = ?

Solution:

As the chemist needs to prepare 250 mL of solution from 6.00 M ammonium hydroxide solution to prepare a 2.50 M aqueous solution of ammonium hydroxide.

Now

first he have to determine the amount of ammonium hydroxide solution that will be taken from6.00 M ammonium hydroxide solution

For this Purpose we use the following formula

                    M1V1=M2V2

Put values from given data in the formula

                   6 x V1 = 2.5 x 250

Rearrange the equation

                   V1 = 2.5 x 250 /6

                    V1 = 104 mL

So 104 mL is the volume of the solution which we have to take from the 6.00 M ammonium hydroxide solution to prepare 2.5 M  aqueous solution of ammonium hydroxide

But we have to prepare 250 mL of the solution.

so the chemist will take 104 mL from 6.00 M ammonium hydroxide solution and have to add 146 mL water to make 250 mL of new solution.

in this question you have to tell about the amount of water that is 146 mL

250 mL (total solution)  = 104 mL (stock solution)  + 146 mL (water)

7 0
3 years ago
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