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Romashka [77]
2 years ago
9

If you want to replicate another scientist's experiment, which sections of their laboratory report will provide you with the mos

t valuable information?
Physics
1 answer:
bogdanovich [222]2 years ago
6 0
If research results can be replicated, it means they are more likely to be correct. Replication is important in science so scientists can “check their work.” The result of an investigation is not likely to be well accepted unless the investigation is repeated many times and the same result is always obtained.
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Explain Newton's third law in your own words.
Kazeer [188]
Newton's third law states "for every action, there is an equal and opposite reaction."

What this is pretty much saying is that for every action, there is a consequence. One force connects and triggers another.
5 0
3 years ago
Read 2 more answers
Fbejfsjnvfdjbesjkbf dsjlbc dsjlc
pav-90 [236]

Answer:

???

Explanation:

7 0
3 years ago
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What are two conductive materials separated by an insulator,and used to store electric potential energy?
jeka94
That's a not-bad description of a capacitor.
5 0
3 years ago
Which statement is true for a car that first goes around a curve of radius r at a constant speed v, and then goes around the sam
sasho [114]
Centripetal force is equal to (mv^2)/r
The way I use to answer these question is to set every variable to 1
m=1
v=1
r=1
so centripetal force =1
then change the variable we're looking at
and since we're find when it's half we could either change it to 1/2 or 2, but 2 is easier to use
m=1
v=2
r=1
((1)×(2)^2)/1=4
So the velocity in the 1st part is half the velocity in the 2nd part and the centripetal force is 4× less
The answer is the centripetal force is 1/4 as big the second time around
3 0
3 years ago
A charge q1 of -5.00 x 10^-9 C and a charge q2 of -2.00x 10^-9 C are separated by a distance of 40.0 cm. Find the equilibrium po
aleksandrvk [35]

Answer:

Explanation:

Let the equilibrium position of third charge be x distance from q₁.

Force on third charge due to q₁

= 9 x 10⁹ x 5 x 10⁻⁹ x 15 x 10⁺⁹ / x²

Force on third charge due to q₂

= 9 x 10⁹ x 2 x 10⁻⁹ x 15 x 10⁺⁹ /( .40-x)²

Both the force will act in opposite direction and for balancing , they should be equal.

9 x 10⁹ x 5 x 10⁻⁹ x 15 x 10⁺⁹ / x² = 9 x 10⁹ x 2 x 10⁻⁹ x 15 x 10⁺⁹ /( .40-x)²

5  / x² = 2 / ( .4 - x )²

Taking square root on both sides

2.236 / x = 1.414 / .4 - x

2.236 ( .4 - x ) = 1.414 x

.8944 - 2.236 x = 1.414 x

.8944 = 3.65 x

x = .245 m

24.5 cm

So the third charge should be at a distance of 24.5 cm from q₁ .

4 0
2 years ago
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