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Nesterboy [21]
2 years ago
13

5. A single slit illuminated with a 500 nm light gives a diffraction pattern on a far screen. The 5th minimum occurs at 7.00° aw

ay from the central maximum. At what angle does the 18th minimum occur? A) 26.0° B) 1.94° C) 5.05° D) 0.44°
Physics
1 answer:
abruzzese [7]2 years ago
3 0

For a single slit illuminated with a 500 nm light gives a diffraction pattern on a far screen,the angle  is mathematically given as

theta=25.3

Option A is correct

<h3> What angle does the 18th minimum occur?</h3>

Generally, the equation for the the angle   is mathematically given as

\theta=n(\lambda/d)

Therefore

\theta 1/ \theta 2=n1(\lambda/d)/ n2(\lambda/d)

In conclusion

theta/7=16/5

theta=10*7/5

theta=25.3

Read more about Angle

brainly.com/question/14362353

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Stairway must have uniform riser height and tread depth; variations in riser height or tread depth shall not be over _______ inc
alexandr1967 [171]

Answer:

\frac{3}{8} inches

Explanation:

the variations in riser height or tread depth should not be grater than \frac{3}{8} inches that is equal to 9.5 mm but the maximum riser height should be the  \frac{81}{4} inch  but variation in riser height should not exceed to \frac{3}{8} inches. The minimum riser height should be 7 inches which is equal to the 178 mm

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3 years ago
A large helium filled balloon is used as the center piece for a graduation party. The balloon alone has a mass of 225 kg and it
Orlov [11]

To solve this problem it is necessary to apply the concepts related to Newton's second law, the definition of density and sum of forces in bodies.

From Newton's second law we understand that

F= ma (\rightarrow Gravity at this case)

Where,

m = mass

a= acceleration

Also we know that

\rho = \frac{m}{V} \Rightarrow m = \rho V

Part A) The buoyant force acting on the balloon is given as

F_b = ma

As mass is equal to the density and Volume and acceleration equal to Gravity constant

F_b = \rho V g

F_b = 1.2*323*9.8

F_b = 3798.5

PART B) The forces acting on the balloon would be given by the upper thrust force given by the fluid and its weight, then

F_{net} = F_b -W

F_{net} = F_b -(mg+\rho_H Vg)

F_{net} = 3798.5-(9.8*225*9.8*0.179*323)

F_{net} = 1030N

PART C) The additional mass that can the balloon support in equilibrium is given as

F_{net} = m' g

m' =\frac{F_{net}}{g}

m' = \frac{1030}{9.8}

m' = 105Kg

4 0
3 years ago
What is the escape speed of an electron launched from the surface of a 1.1-cm-diameter glass sphere that has been charged to 8.0
zimovet [89]
At surface,
v = kq/r

And potential energy of an electron is given by,
PE = -ev = -ekq/r

At escape velocity,
PE + KE = 0.
Therefore,
1/2mv^2 - ekq/r =0
1/2mv^2 = ekq/r
v = Sqrt [2ekq/mr], where v = escape velocity, e = 1.6*10^-19 C, k = 8.99*10^9 Nm^2/C^2, m = 9.11*10^-31 kg, r = 1.1*10^-2 m, q = 8*10^-9 C

Substituting;
v = Sqrt [(2*1.6*19^-19*8.99*10^9*8*10^-9)/(9.11*10^-31*1.1*10^-2)] = 47949357.23 m/s ≈ 4.795 *10^7 m/s
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3 years ago
The moon continues to orbit Earth in an example of the law of conservation of
marusya05 [52]
A gravity and or D angular momentum

7 0
3 years ago
Read 2 more answers
A woman drops a vibrating tuning fork, which is vibrating at 513 Hertz, from a tall building. Through what distance (in m) has t
umka21 [38]

Answer:

h = 15.34 m

Explanation:

given,

tuning fork vibration = 513 Hz

speed of sound = 343 m/s

frequency after deflection = 489 Hz

the source (the fork) moves away from the observer, its speed increases and hence the apparent frequency decreases

f_{apparent} = \dfrac{v}{v+u}f_0

489 = \dfrac{343}{343+u}\times 513

0.953 = \dfrac{343}{343+u}

343+u = \dfrac{343}{0.953}

343+u = 359.92

u = 16.92 m/s

height of the building

v² = u² + 2 g s

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h = 14.61 m

time taken by sound to reach observer

t = \dfrac{14.61}{343}

t =0.0426\ s

in this time tuning fork has fallen one more now,

h' = u t + \dfrac{1}{2}gt^2

h' = 16.92\times 0.0426 + \dfrac{1}{2}\times 9.8 \times 0.0426^2

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total distance

      h = 14.61 + 0.73

      h = 15.34 m

6 0
3 years ago
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