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KatRina [158]
3 years ago
5

In the lab vinegar acetic acid was mixed with baking soda sodium bicarbonate to form dioxide gas and sodium acetate. What are th

e products?
Chemistry
1 answer:
SpyIntel [72]3 years ago
4 0

2CH3COOH +Na2CO3 ----> 2CH3COONa + H20 + CO2

know you can find what all products formed from his reaction

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Question:
anzhelika [568]

Answer:

A. Chemical

B. physical

Explanation:

7 0
3 years ago
Dinitrogen pentoxide gas is formed by the reaction of nitrogen trioxide gas and nitrogen dioxide gas balanced equation
leonid [27]

Answer:

Balanced chemical  equation:

NO₂ + NO₃ → N₂O₅

Explanation:

Chemical equation:

NO₂ + NO₃ → N₂O₅

Balanced chemical  equation:

NO₂ + NO₃ → N₂O₅

Nitrogen trioxide gas combine with nitrogen dioxide gas and form nitrogen pentoxide.

This is the simple synthesis reaction in which two substance combine to form a new substance.

Synthesis reaction:

It is the reaction in which two or more simple substance react to give one or more complex product.

General chemical equation:

A + B  → AB

A and B are reactants that combine to form AB product.

7 0
3 years ago
What kind of sport do you have interest the most and explain why? <br>​
lidiya [134]

Answer

Gymnastics

Explanation:

for the simple fact that they do cool stuff

7 0
2 years ago
Would the N=O bond in HNO2 be longer, shorter, or the same length as the N-O bonds in NO2-?
aivan3 [116]

Explanation:

Bond order is inversely proportional to the bond length.

B.O\propto \frac{1}{B.L}

In HNO_2 molecule. one nitrogen is double bonded to nitrogen and one oxygen is single bonded to nitrogen and hydrogen bond.

  • Bond order between the (N=O) bond is 2 which means that bond length between the (N=O) bond is shorter than that of the N-O bond.
  • Bond order between the (N-O) bond is 1 which means that bond length of the N-O bond is longer than that of the bond length of (N=O) bond.
3 0
3 years ago
Read 2 more answers
Consider the reaction between hydrogen gas and chlorine gas to form hydrogen chloride gas in a closed cylinder with a movable pi
d1i1m1o1n [39]

Answer:

In this case, the system doesn't be affected by the pressure change. This means that nothing will happen

Explanation:

We can answer this question applying the Le Chatelier's Principle. It says that changes on pressure, volume or temperature of an equilibrium reaction will change the reaction direction until it returns to the equilibrium condition again.

The results of these changes can define as:

Changes on pressure: the reaction will move depending the quantity of moles on each side of the reaction

Changes on temperature: The reaction will move depending on if it's endothermic or exothermic

Changes on volume: The reaction will move depending the limit reagent  and the quantity of moles on each side of the reaction

In the exercise, they mention a change on pressure of the system at constant temperature (that means the temperature doesn't change). As Le Chatelier Principle's says, we must analyze what happens if the pressure increase or decrease. If pressure increase the reaction will move on the side that have less quantity of moles, otherwise, if the pressure decreases the reaction will move to the side that have more quantity of moles. In this case, we can see that both sides of the equation have the same number of moles (2 for the reactants and 2 for the products). So, in this case, we can conclude that, despite the change on pressure (increase or decrease), nothing will happen.

3 0
2 years ago
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