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ycow [4]
3 years ago
9

A ___ force is not path-dependent and does not change the overall mechanical energy of an object.​

Physics
2 answers:
finlep [7]3 years ago
6 0

Answer:

conservative

Explanation:

Nonconservative force is the force that depends on a path, however conservative does not depend on a path and it is not associated with the potential energy. When the work is done by an unconservative force, mechanical energy is added or removed. Friction is the best example for a non-conservative force. When these non-conservative forces are acting, the mechanical energy changes but these are not preserved.

hope this helped!

Margaret [11]3 years ago
4 0

Answer: conservative

Explanation:

A conservative force is not path-dependent and does not change the overall mechanical energy of an object.​

A conservative force is a force with the property that the total work done in moving a particle between two points is independent of the taken path, e.g. gravitational force or electric force.

A nonconservative force is one for which work depends on the path taken, e.g. frictional force.

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A block of mass 0.500 kg is pushed against a horizontal spring of negligible mass until the spring is compressed a distance x (F
Marrrta [24]

Answer:

Part a)

x = 0.4 m

Part b)

v_i = 11.7 m/s

Part c)

Speed is more than the required speed so it will reach the top

Explanation:

Part a)

As we know that there is no frictional force while block is moving on horizontal plane

so we can use energy conservation on the block

\frac{1}{2}mv^2 = \frac{1}{2}kx^2

\frac{1}{2}0.500(12^2) = \frac{1}{2}(450)x^2

x = 0.4 m

Part b)

If the track has average frictional force of 7 N then work done by friction while block slides up is given as

W_f = -7( \pi R)

W_f = -7(\pi \times 1.00)

W_f = -22 J

work done against gravity is given as

W_g = - mg(2R)

W_g = -(0.500)(9.8)(2\times 1)

W_g = -9.8 J

Now by work energy equation we have

\frac{1}{2}mv_i^2 + W_f + W_g = \frac{1}{2}mv_f^2

\frac{1}{2}0.5(12^2) - 9.8 - 22 = \frac{1}{2}(0.5)v_f^2

v_f = 4.1 m/s

Part c)

now minimum speed required at the top is such that the normal force must be zero

mg = \frac{mv^2}{R}

v = \sqrt{Rg}

v = 3.13 m/s

so here we got speed more than the required speed so it will reach the top

5 0
3 years ago
What is the momentum of an 18-kg object moving at 0.5 m/s?
Otrada [13]

sorry Idk the answer ..???

6 0
3 years ago
A 40kg dog is sitting on top of a hillside and has a potential energy of 1,568 J. What is the height of the hill side?
bagirrra123 [75]

Answer:

<h2>39.2 m</h2>

Explanation:

The height of the hill side can be found by using the formula

h =  \frac{p}{m}  \\

p is the potential energy

m is the mass

From the question we have

h =  \frac{1568}{40}  =  \frac{196}{5}  \\

We have the final answer as

<h3>39.2 m</h3>

Hope this helps you

5 0
3 years ago
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3 years ago
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