Answer:
3234.2 W
Explanation:
Since intensity I = Power/Area. The intensity of the light from the sun, I = power radiated by sun/area of sphere of radius, r = 1.5 × 10¹¹ m.
So, I = 3.9 10²⁶W/4π(1.5 × 10¹¹ m)² = 2.069 × 10³ W/m².
Now, the power radiated on the patch of area 0.570 m² at the equator is
P = Icos27/A = 2.069 × 10³ W/m² cos27/0.570 m² = 1843.49/0.570 = 3234.2 W
We know the answer doesn't have to do with force because we have not identified a positive or negative axis.
Depending on what the system we are evaluating is, the sign of the work can change.
If work is done on the system, it is negative, but if work is done by the system, it is positive.
If the system we are evaluating is the leash, the work is being done by the leash, and therefore, the work is positive.
If the system we are evaluating is the dog, the work is being done on the dog, and therefore, the work is negative.
Answer:
Detailed explanation:
Density of water=1000kg/m³
Hence mass of water displaced is:
m=d×v
=1000kg/m³×(4.3×10^-3)m³ (volume of water displaced converted to L)
=4.3 kg of water
Hence, mass of football is also 4.3 kg(Archimedes principle)
Thus density of football
=mass÷volume
substitute the mass and volume and solve.
hope this helps
Answer:
option B
Explanation:
The correct answer is option B
When the displacement in the harmonic motion is maximum then kinetic energy at the maximum point is minimum and the potential energy is maximum at that point.
So, when the displacement is maximum, spring force magnitude is also maximum because the force is proportional to the displacement and also the magnitude of the acceleration is maximum so, the net force is also maximum.
Answer:
heat required in pan B is more than pan A
Explanation:
Heat required to raise the temperature of the substance is given by the formula
now we know that both pan contains same volume of water while the mass of pan is different
So here heat required to raise the temperature of water in Pan A is given as
Now similarly for other pan we have
So here by comparing the two equations we can say that heat required in pan B is more than pan A
