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hodyreva [135]
3 years ago
12

10. Which is a practical application of freezing-point depression?

Chemistry
1 answer:
IceJOKER [234]3 years ago
5 0

Answer:

1.

Explanation:

its the practical example

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Do elements of the halogen family lose one electron to become halide ions
lana66690 [7]
Its on Google..."The group number of a representative element in the periodic table is related to the number of valence electrons it has. ... Elements of the halogen family lose one electron to become halide ions."
5 0
3 years ago
PLEASE HELP ME ASAPP!!
aliina [53]

Conduction-

putting an icepack on injury

grabbing a warm coffee mug

burning yourself by touching boiling water

the handle of a pot being to hot to touch

Convection-

heat from a fire to warm hands

warm water rising to the surface of of the ocean etc.

warm air rising off pavement

an oven that cooks by cycling warm air through the bottom and out the top

Radiation-

cooking popcorn using microwave

heat from the sun hitting a solar panel

( i havent done science in a while cuz im homeschooled but i think most of these are correct)

good luck on what your working on !!

7 0
3 years ago
A mixture of gaseous CO and H2, called synthesis gas, is used commercially to prepare methanol (CH3OH), a compound considered an
mr_godi [17]

Answer : The value of equilibrium constant (K) is, 424.3

Explanation :  Given,

Concentration of H_2 at equilibrium = 0.067 mol

Concentration of CO at equilibrium = 0.021 mol

Concentration of CH_3OH at equilibrium = 0.040 mol

The given chemical reaction is:

CO+2H_2\rightarrow CH_3OH

The expression for equilibrium constant is:

K_c=\frac{[CH_3OH]}{[CO][H_2]^2}

Now put all the given values in this expression, we get:

K_c=\frac{(0.040)}{(0.021)\times (0.067)^2}

K_c=424.3

Thus, the value of equilibrium constant (K) is, 424.3

4 0
3 years ago
What mass of sodium chloride is needed to prepare 200 ml of a 0.1 M solution
Nikolay [14]

Answer:

C. 1.17 grams

Explanation:

  • The molarity is the no. of moles of solute in a 1.0 L of the solution.

<em>M = (mass/molar mass)solute x (1000/ V)</em>

M = 0.1 M, mass = ??? g, molar mass of NaCl = 58.44 g/mol, V = 200.0 mL.

∴ mass of NaCl = (M)(molar mass)(V)/1000 = (0.1 M)(58.44 g/mol)(200.0 mL)/1000 = 1.168 g ≅ 1.17 g.

5 0
3 years ago
Read 2 more answers
Compare which element would have larger first ionization energy: an alkali metal in Period 2 or an alkali metal in Period 4?
maria [59]

Answer:

An alkali metal present in period 2 have larger first ionization energy.

Explanation:

Ionization energy:

The amount of energy required to remove the electron from the atom is called ionization energy.

Trend along period:

As we move from left to right across the periodic table the number of valance electrons in an atom increase. The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases because it is very difficult to remove the electron from atom and more energy is required.

Trend along group:

As we move down the group atomic radii increased with increase of atomic number. The addition of electron in next level cause the atomic radii to increased. The hold of nucleus on valance shell become weaker because of shielding of electrons thus size of atom increased.

As the size of atom increases the ionization energy from top to bottom also  decreases because it becomes easier to remove the electron because of less nuclear attraction and as more electrons are added the outer electrons becomes more shielded and away from nucleus.  Thus alkali metal present in period 2 have larger ionization energy because of more nuclear attraction as compared to the alkali metal present in period 4.

6 0
2 years ago
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