Question

A mixture of gaseous CO and H2, called synthesis gas, is used commercially to prepare methanol (CH3OH), a compound considered an alternative fuel to gasoline. Under equilibrium conditions at 540.2 K, [H2] = 0.067 mol [CO]=0.021 mol/L and [CH3OH]=0.040 mol/L what is the value of Kc for this reaction at 505.0 K?

Answer 1

Answer : The value of equilibrium constant (K) is, 424.3

Explanation :  Given,

Concentration of $H_2$ at equilibrium = 0.067 mol

Concentration of $CO$ at equilibrium = 0.021 mol

Concentration of $CH_3OH$ at equilibrium = 0.040 mol

The given chemical reaction is:

$CO+2H_2\rightarrow CH_3OH$

The expression for equilibrium constant is:

$K_c=\frac{[CH_3OH]}{[CO][H_2]^2}$

Now put all the given values in this expression, we get:

$K_c=\frac{(0.040)}{(0.021)\times (0.067)^2}$

$K_c=424.3$

Thus, the value of equilibrium constant (K) is, 424.3