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1 year ago

How many grams of sodium (na ) would be needed to create a 100 millimole concentration in one liter?

Chemistry

1 answer:

Rina8888 [55]1 year ago

7 0

2.3g of sodium would be needed to create a 100 millimole concentration in one liter.

Given,

Mole of Na+ = 100 millimole

As we know that,

1 millimole = 10 -³ mole

Mole of Na+ in 100 millimoles = 100 × 10 -³ mole

= 0.1mole

Mole is defined as the ratio of mass of Na+ to the molar mass of sodium.

<h3>What is Molar Mass? </h3>

The molar mass is defined as the sum of the total mass in grams unit of the atoms present to make a molecule per mole.

Mole of Na+ = mass of Na + / molar mass of Na +

0.1 = mass of Na + / 22.99 gl mol

Mass of Na + = 0.1 × 22.99

= 2.299 g

Mass of Na + = 2.3 g

Thus, we calculated that 2.3g of sodium would be needed to create a 100 millimole concentration in one liter.

learn more about moles:

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Fe(s) + CuSO4(aq) <===> Cu(s) + FeSO4(aq)

Ludmilka [50]

Answer : The original concentration of copper (II) sulfate in the sample is, $5.6\times 10^{-1}g/L$

Explanation :

Molar mass of Cu = 63.5 g/mol

First we have to calculate the number of moles of Cu.

Number of moles of Cu = $\frac{\text{Mass of Cu}}{\text{Molar mass of Cu}}=\frac{89\times 10^{-3}g}{63.5g/mol}=1.40\times 10^{-3}mole$

Now we have to calculate the number of moles of $CuSO_4$

Number of moles of Cu = Number of moles of $CuSO_4$

Number of moles of $CuSO_4$ = $1.40\times 10^{-3}mole$

Now we have to calculate the molarity of $CuSO_4$

$\text{Molarity}=\frac{\text{Moles of }CuSO_4\times 1000}{\text{Volume of solution (in mL)}}$

Now put all the given values in this formula, we get:

$\text{Molarity}=\frac{1.40\times 10^{-3}mole\times 1000}{400.mL}=0.0035M$

To change mol/L into g/L, we need to multiply it with molar mass of $CuSO_4$

Molar mass of $CuSO_4$ = 159.609 g/mL

Concentration in g/L = $0.0035M\times 159.609g/mol=0.5586g/L\approx 5.6\times 10^{-1}g/L$

Thus, the original concentration of copper (II) sulfate in the sample is, $5.6\times 10^{-1}g/L$

3 0

2 years ago

A sample of an ionic compound that is often used as a dough conditioner is analyzed and found to contain 4.628 g of potassium, 9

Roman55 [17]

Answer:

The empirical formula of the compound is = $KBrO_3$

The name of the compound is potassium bromate.

Explanation:

Mass of potassium = 4.628 g

Moles of potassium = $\frac{4.628 g}{39 g/mol}=0.1187 mol$

Mass of bromine = 9.457 g

Moles of bromine = $\frac{9.457 g}{80 g/mol}=0.1182 mol$

Mass of oxygen = 5.681 g

Moles of oxygen = $\frac{5.681 g}{16 g/mol}0.3551$

For empirical formula of the compound, divide the least number of moles from all the moles of elements present in the compound:

Potassium :

$\frac{0.1187 mol}{0.1182 mol}=1.0$

Bromine;

$\frac{0.1182 mol}{0.1182 mol}=1.0$

Oxygen ;

$\frac{0.3551 mol}{0.1182 mol}=3.0$

The empirical formula of the compound is = $KBrO_3$

The name of the compound is potassium bromate.

5 0

3 years ago

Why is oxygen an element ? a it is essential to life b it burn c it combines with hydrogen d it cannot be broken down into a sim

MrRa [10]

D.) It cannot be broken down into a simple substance through chemical means...

5 0

2 years ago

Read 2 more answers

Picric acid has been used in the leather industry and in etching copper. However, its laboratory use has been restricted because

olchik [2.2K]

Answer:

0.3023 M

Explanation:

Let Picric acid = $H_{picric}$

So, $H_{picric}$ + $H_2}O$ ⇄ $H_3}O^+$ + $Picric^-$

The ICE table can be given as:

$H_{picric}$ + $H_2}O$ ⇄ $H_3}O^+$ + $Picric^-$

Initial: 0.52 0 0

Change: - x + x + x

Equilibrium: 0.52 - x + x + x

Given that;

acid dissociation constant ( $K_a$ ) = 0.42

$K_a = \frac{[H_3O^+][Picric^-]}{H_{picric}}$

$0.42 = \frac{[x][x]}{0.52-x}}$

$0.42 = \frac{[x]^2}{0.52-x}}$

0.42(0.52-x) = x²

0.2184 - 0.42x = x²

x² + 0.42x - 0.2184 = 0 -------------------- (quadratic equation)

Using the quadratic formula;

$\frac{-b+/-\sqrt{b^2-4ac} }{2a}$ ; ( where +/- represent ± )

= $\frac{-0.42+/-\sqrt{(0.42)^2-4(1)(-0.2184)} }{2*1}$

= $\frac{-0.42+/-\sqrt {0.1764+0.8736} }{2}$

= $\frac{-0.42+\sqrt {1.0496} }{2}$ OR $\frac{-0.42-\sqrt {1.0496} }{2}$

= $\frac{-0.42+1.0245}{2}$ OR $\frac{-0.42-1.0245}{2}$

= $\frac{0.6045}{2}$ OR $-\frac{1.4445}{2}$

= 0.30225 OR - 0.72225

So, we go by the +ve integer that says:

x = 0.30225

x = [ $H_3}O^+$ ] = [ $Picric^-$ ] = 0.3023 M

∴ the value of [H3O+] for an 0.52 M solution of picric acid = 0.3023 M (to 4 decimal places).

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3 years ago

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MA_775_DIABLO [31]

Answer:

B. Design homes that can be built on stilts where flooding is likely to occur.

C. Replace power lines that have been damaged by severe weather.

Explanation:

$Hope$ $this$ $helps!$ $:)$

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2 years ago