I believe the answer you are looking for is Static Friction. Static Friction is the force that holds an object in place until it starts to move. Then it switches to rolling friction.
For example, if you have a 1/2 ton truck sitting in front of you and the truck is in neutral. (meaning it can roll if pushed). The truck is extremely hard to move at first. That is because static friction is holding it in place until the amount of force exceeds the limit of static friction.
So if we continue to push at the truck and you feel it starting to move, then once it starts moving it is much easier to push, that is because we moved past static friction to rolling friction. Rolling friction is what helps slow things down. If you roll a ball across a carpet floor it eventually comes to a stop.
What kind of question is this
Answer:
The correct answer is m= mol solute kg soivent
Explanation:
Molality is a measure of concentration, which indicates the moles of solute (in this case sodium hydroxide) in 1kg of solvent .
In this case:
0,800 kg water-----0,400 mol NaOH
1 ,000 kg water ---x=(1 ,000 kg water x 0,400 mol NaOH)/0,800 kg water
x=0,5 mol NaOH---> <em>The solution is 0,5 molal (0,5 m)</em>
Answer:
10g Carbon has more particles.
Explanation:
To Find
Which has more particles 10g of C or 10g of Ca
The molar mass of carbon is 12g and Calcium is 40g.
1 mole of atom , molecule or ions contain Avagadro number (6.022×10∧23) of particles and also have a mass equal to it's molar mass.
For C,
12g C will have 6.022×10∧23 atoms
10g C will have
×6.022×10∧23 atoms
=0.833 × 10∧23 atoms
For Ca,
1 mole Ca =40g
40g Ca will have 6.022×10∧23 atoms
10g Ca will have
×6.022×10∧23 atoms
=0.25 × 6.022×10∧23 atoms
Resonance structures show that chemical species have equal bond lengths and bond angles when in resonance. The bond lengths of the N - O bond in HNO2 is 126pm.
Linus Pauling introduced the idea of resonance to explain the nature of bonding in compounds and ions where a single Lewis structure can not satisfactorily account for the observed properties of the chemical species.
If the two structures are resonance structures, they will have equal N - O bond lengths and bond angles. The bond length will be intermediate between that of a pure N - O single and N - O double bond. The actual N- O bond lengths in HNO2 are obtained as; 136 pm - 122 pm/2 = 126 pm.
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