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LiRa [457]
3 years ago
8

Is is false or true The closer objects are, the stronger the gravitational force between them.

Physics
1 answer:
____ [38]3 years ago
5 0

Answer:

<em>TRUE</em>

Explanation:

The gravitational force between two objects becomes<u><em> weaker</em></u><em> if the two objects are </em><u><em>moved apart</em></u> and <em>stronger</em><em> if they are brought </em><em>closer</em><em> together</em>; that is, the force depends on the distance between the objects

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A spring has a spring constant of 90N/m.How much potential energy does it store when stretched by 2 cm?
il63 [147K]

Answer:

The potential energy stored in the spring is 0.018 J.

Explanation:

Given;

spring constant, k = 90 N/m

extension of the spring, x = 2 cm = 0.02 m

The potential energy stored in the spring is calculated as;

U = ¹/₂kx²

where;

U is the potential energy stored in the spring

Substitute the given values in the equation above;

U = ¹/₂  x  90 N/m  x  (0.02 m)²

U = 0.018 J

Therefore, the  potential energy stored in the spring is 0.018 J.

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3 years ago
A typical white dwarf is __________. A typical white dwarf is __________. about the same size and mass as the Sun but much hotte
Ulleksa [173]

Answer:

A typical white dwarf is about as massive as the Sun, yet only slightly bigger than the Earth.

Explanation:

A typical white dwarf is about as massive as the Sun, yet only slightly bigger than the Earth.

White dwarfs are one of the densest elements in the universe, surpassed only by neutron stars and black holes. They can be considered as medium mass stars that fuses hydrogen into helium

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3 years ago
Why exactly do people use simple <br> machines like a pulley
Komok [63]
They can change the direction of force which can result in easier movement.
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3 years ago
A physics student throws a ball thrown horizontally from the top of a building with a speed of 8 m/s. The student measures the h
Alekssandra [29.7K]

Answer:

Following are the solution to the given question:

Explanation:

Please find the complete question in the attached file.

a_x = 0\\\\a_y = -g = -9.81\ \ \frac{m}{s^2} \\\\v_{iy} = 0 \\\\y = v_{iy} \times t+ \frac{1}{2ay} \times t^2 \\\\ 15 = \frac{1}{2} \times 9.8 \times t^2 \\\\t = \sqrt{(2 \times \frac{15}{9.8})} \\\\

  = 1.75 \ sec \\\\

Distance:

x = v_{ix} \times t \\\\

  = 8 \times 1.75\\\\= 14 m

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