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LiRa [457]
4 years ago
8

Is is false or true The closer objects are, the stronger the gravitational force between them.

Physics
1 answer:
____ [38]4 years ago
5 0

Answer:

<em>TRUE</em>

Explanation:

The gravitational force between two objects becomes<u><em> weaker</em></u><em> if the two objects are </em><u><em>moved apart</em></u> and <em>stronger</em><em> if they are brought </em><em>closer</em><em> together</em>; that is, the force depends on the distance between the objects

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Please help , will surely mark As brainlest
Oliga [24]
The north arrow of the compasses will all point to the south since opposite poles attract. I have put an example picture below.

For the horse shoe magnet the magnetic field line will also go from north to south. I have put a picture of this below



8 0
3 years ago
Name an example of a population you might find in a forest.
ki77a [65]

Answer:

deers...?

Explanation:

7 0
3 years ago
Read 2 more answers
A basketball rolls without slipping (starting from rest) down a ramp. If the ramp is sloped by an angle of 4 degrees above the h
slavikrds [6]

Answer:

11.7 m/s

Explanation:

To find its speed, we first find the acceleration of the center of mass of a rolling object is given by

a = gsinθ/(1 + I/MR²) where θ = angle of slope = 4, I = moment of inertia of basketball = 2/3MR²

a = 9.8 m/s²sin4(1 + 2/3MR²/MR²)

  = 9.8 m/s²sin4(1 + 2/3)

  = 9.8 m/s²sin4 × (5/3)

  = 1.14 m/s²

To find its speed v after rolling for 60 m, we use

v² = u² + 2as where u = initial speed = 0 (since it starts from rest), s = 60 m

v = √(u² + 2as) = √(0² + 2 × 1.14 m/s × 60 m) = √136.8 = 11.7 m/s

4 0
3 years ago
Calculate the minimum thickness (in nm) of an oil slick on water that appears blue when illuminated by white light perpendicular
mr_godi [17]

Answer:

The minimum thickness = 83.92 nm

Explanation:

The relation between the wavelength in a particular medium and refractive index \lambda_n = \frac{ \lambda }{n}

where ;

\lambda = wavelength of the light in vacuum

n = refractive index of medium with respect to vacuum

For one phase change :

2t = \frac{\lambda_n}{2}\\\\where \ \lambda_n = \frac{\lambda}{n}\\\\Then \ \\\\2t = \frac{\lambda}{2n}\\\\t = \frac{\lambda_n}{4n}

Replacing 1.43 for n and 480 nm for λ; we have:

t = \frac{480}{4(1.43)}

t = 83.92 nm

Thus; the minimum thickness = 83.92 nm

4 0
3 years ago
Light of wavelength 550 nm falls on a
Brums [2.3K]

Answer:

The first diffraction maximum fringe will be at approximately 2.7 meters from the central maximum.

Explanation:

We can describe single slit diffraction phenomenon with the equation:

a\sin\theta=m\lambda (1)

with θ the angular position of the minimum of order m respect the central maximum, a the slit width and λ the wavelength of the incident light. Because the distances between the first minima and the central maximum (y_{m}) are small compared to the distance between the screen and the slit (x), we can approximate \sin\theta\approx\tan\theta=\frac{y}{x}, using this on (1):

a\frac{y_{m}}{x}=m\lambda

solving for y

y_{m}= \frac{mx\lambda}{a}

Note that y_{m}is the distance between a minimum and the central maximum but we need the position of a maximum not a minimum, here we can use the fact that a maximum is approximately between two minima, so the first diffraction maximum fringe is between the minima of order 1 and 2, so we should find y_{1}, y_{2} add them and divide by two:

y_{1}= \frac{(1)(10.0m)(550\times10^{-9}\,m)}{3.00\times10^{-6}\,m}

y_{1}= 1.8 m

y_{2}= \frac{(2)(10.0m)(550\times10^{-9}\,m)}{3.00\times10^{-6}\,m}

y_{1}= 3.6 m

maximum = \frac{1.8+3.6}{2}=2.7m

7 0
3 years ago
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