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arlik [135]
3 years ago
5

While exploring a castle, Xena the Exterminator is spotted by a dragon who chases her down a hallway. Xena runs into a room and

attempts to swing the heavy door shut before the dragon gets her. The door is initially perpendicular to the wall, so it must be turned through 90∘ to close. The door has a height of 3.10 m and a width of 1.20 m , and its weight is 730 N . You can ignore the friction at the hinges.
If Xena applies a force of 220 N at the edge of the door and perpendicular to it, how much time does it take her to close the door?
Physics
1 answer:
nexus9112 [7]3 years ago
4 0

Answer:

.65 s

Explanation:

Torque will create angular acceleration in the door .

Torque = force x perpendicular distance from the hinge

= 220 x 1.2 = 264 Nm

Moment of inertia of the door about hinge

I = 1 /3 x m l²

m is mass of the door and l is its width

=  \frac{730\times1.2\times1.2}{3\times9.8}

= 35.755 kg m²

Angular acceleration α = Torque / moment of inertia

= \frac{264}{35.755}

= 7.38 rad s²

Angle to be rotated θ = π/2

π/2 = .5 α t²

1.56 = .5 x 7.38 t²

t = 0.65 s

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A shopper in a supermarket pushes a loaded 31 kg cart with a horizontal force of 12 N. The acceleration of gravity is 9.81 m/s 2
rosijanka [135]

Answer:

3.41334 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

m = Mass

Force

F=ma\\\Rightarrow a=\frac{F}{m}\\\Rightarrow a=\frac{12}{31}\\\Rightarrow a=0.387\ m/s^2

Acceleration of the cart is 0.387 m/s²

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3 0
3 years ago
If 40.0 kj of energy are absorbed by .500 kg of water 10 degrees c, what is the final temperature of the water?
anastassius [24]

To solve the problem, we must use the following equation:

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where

Q is the amount of heat energy absorbed by the water

m is the mass of the water

Ti and Tf are the initial and final temperature

Cs is the specific heat capacity of the water

The data we have in this problem are:

Q=40.0 kJ

C_s =4.186 kJ/kg^{\circ}C

T_i=10^{\circ}C

m=0.500 kg

Substituting the data into the equation and re-arranging it, we find

T_f = T_i + \frac{Q}{mC_s}=10^{\circ}+\frac{40.0 kJ}{(0.500 kg)(4.186 kJ/kg^{\circ}}=29.1^{\circ}C

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Suppose the experiment was conducted in the same manner, but the axle was now off center of the solid disk. Would you expect the
san4es73 [151]

Answer:

Explanation:

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I = Ig + Md²

where M is mass of the body and d is distance between two parallel axis.

So I is greater than Ig.

4 0
3 years ago
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