Answer:
reading would be 5.413 m.
Explanation:
Given:-
- The actual distance from ruler to an object is d = 24.0 m
- The adiabatic bulk modulus, B = 2.37 *10^9 Pa
- The density of seawater, ρ = 1025 kg/m^3
- The preset value of speed of sound in air, v_th = 343 m/s.
Find:-
Determine the distance reading that the ruler displays.
Solution:-
- We will first determine the actual speed of the sound ( v_a) in sea-water which can be determined from the following formula:
v_a = √ (B / ρ )
- Plug in the values in the relationship above and compute v_a:
v_a = √ ( 2.37 *10^9 / 1025 )
v_a = 1520.59038 m/s
- The time taken (t) for for the sound to travel from source(ruler) to an object which is d distance away.
d = v_a*t
t = d / v_a
t = 24.0 / 1520.59038
t = 0.01578 s
- The distance reading on the ruler would be preset speed (v_th) of sound in air multiplied by the time taken(t).
reading = v_th*t
reading = (343)*(0.01578)
= 5.413 m
Answer:
Kinetic frictional force will be equal to 56.84 N
Explanation:
We have given mass of the skier m = 58 kg
Acceleration due to gravity 
Coefficient of kinetic friction 
We have to find the kinetic frictional force
Kinetic frictional force is given by

So kinetic frictional force will be equal to 56.84 N
Answer:
see below
Explanation:
First: Leave a couple inches of wire loose at one end and wrap most of the rest of the wire around iron u-shaped bar and make sure not to overlap the wires.
Second:Cut the wire (if needed) so that there is about a couple inches loose at the other end too.
Third: Now remove about an inch of the plastic coating from both ends of the wire and connect the one wire to one end of a battery and the other wire to the other end of the battery.
This depends on the direction of the velocity vector to the magnetic field vector. The force is F=q(VxB) ("x" is the cross product.) The max force is when V and B are perpendicular. Then F=qVB = (1.602e-19)(2000)(300) = 9.612e-14 N
Answer: potassium
Explanation: An atom of potassium would have a very easy time losing one electron to form an ionic bond with an atom of an element that would easily accept it.