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liq [111]
3 years ago
7

Why can Muhammad exert a greater punching force with his bare fist than he can while wearing a

Physics
1 answer:
weqwewe [10]3 years ago
5 0

Answer:

the glove could be heavy so slowing down his power

Explanation:

JUST GUESSED

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If you stood on a planet with four times the mass of Earth, and twice Earth's radius, how much would you weigh?
nikdorinn [45]

Answer:

1/4 times your earth's weight

Explanation:

assuming the Mass of earth = M

Radius of earth = R

∴ the mass of the planet= 4M

the radius of the planet = 4R

gravitational force of earth is given as = \frac{GM}{R^{2} }

where G is the gravitational constant

Gravitational force of the planet = \frac{G4M}{(4R)^{2} }

                                                       =\frac{G4M}{16R^{2} }

                                                       =\frac{GM}{4R^{2} }

recall, gravitational force of earth is given as = \frac{GM}{R^{2} }

∴Gravitational force of planet = 1/4 times the gravitational force of the earth

you would weigh 1/4 times your earth's weight

3 0
4 years ago
Solenoid is another word for
Artyom0805 [142]
Answer: coil of wire
5 0
3 years ago
How can you use ecozone in a sentence?
beks73 [17]
A large geographical region having a distinct biodiversity<span> of </span>flora<span> and </span>fauna.<span>

</span>
5 0
4 years ago
<img src="https://tex.z-dn.net/?f=%5Cbold%7B%20Choose%20%5C%3A%20the%20%5C%3A%20correct%20%5C%3A%20Answer%20%5C%3A%20%3A%29%20%5
Ulleksa [173]

Answer:

B and B

Explanation:

Question 1:

The distance is a unit of length, such as miles, meters, kilometers

The correct answer for this question would be 8m

Question 2:

Speed has a unit of length per unit of time.

The correct answer for this would be meters per second

-Chetan K

3 0
3 years ago
A Boeing 747 ""Jumbo Jet"" has a length of 59.7 m. The runway on which the plane lands intersects another runway. The width of t
Reika [66]

Answer:

1.7 seconds

Explanation:

To clear the intersection, the total distance to be covered = 59.7 + 25 =84.7m

first we need to find the initial speed to just enter the intersection by using the third equation of motion

v^2 - u^2 = 2*a*s

45^2 - u^2 = 2 * -5.7 * 84.7

u^2 = 45^2 +965.58

u^2 = 2990.58

u = 54.7 m/s

Now for time we apply the first equation of motion

v-u =a * t

t = (v-u)/a = (45 - 54.7)/-5.7 = 1.7seconds

8 0
4 years ago
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