Answer:
b) Projectile MOTION
Explanation:
SHM is periodic motion or to and fro motion of a particle about its mean position in a straight line
In this type of motion particle must be in straight line motion
So here we can say
a) Simple Pendulum : it is a straight line to and fro motion about mean position so it is a SHM
b) Projectile motion : it is a parabolic path in which object do not move to and fro about its mean position So it is not SHM
d) Spring Motion : it is a straight line to and fro motion so it is also a SHM
So correct answer will be
b) Projectile MOTION
The red at the bottom is just the holder for the beaker. It’s not apart of the density.
Given:
The given value is 
.
To find:
The value of the given expression by using the Binomial approximation.
Explanation:
We have,
It can be written as:
![[\because (1+x)^n=1+nx]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%281%2Bx%29%5En%3D1%2Bnx%5D)
Therefore, the approximate value of the given expression is 1.0002.
Here is the answer. What is happening at the atomic level to give rise to the observed energy is that t<span>he </span>atomic level<span> is affected by the movement of electrons so as to </span><span>give rise to the observed energy. Hope this answers your question. Have a great day!</span>
Answer: minimum speed of launch must be 7.45m/s
Explanation:
Given the following:
Height or distance (s) = 2.83m
The final velocity(Vf) at maximum height = 0
Upward motion, acceleration due to gravity(g) us negative = -9.8m/s^2
From the 3rd equation of motion:
V^2 = u^2 - 2gs
Where V = final velocity
u = initial velocity
Therefore, u = Vi
u = √Vf^2 - 2gs
u = √0^2 - 2(-9.8)(2.83)
u = √0 + 55.468
u = √55.468
u = 7.4476 m/s
u = 7.45m/s
