Answer:
4.68x10⁹
Explanation:
Kp is the equilibrium constant based on presure, and depends only on the gas substances. For a generic equation:
aA(g) + bB(g) ⇄ cC(g) + dD(g)
The reaction given can be summed to form the third one:
C(s) + CO₂(g) ⇄ 2CO (g) K'p = 1.30x10¹⁴
CO(g) + Cl₂(g) ⇄ COCl₂ (g) K''p = 6.00x10⁻³
We need to multiply the second reaction by 2, so CO will be simplified. If we multiplied a reaction for n, the new Kp will be (Kp)ⁿ, so:
C(s) + CO₂(g) ⇄ 2CO (g) K'p = 1.30x10¹⁴
2CO(g) + 2Cl₂(g) ⇄ 2COCl₂(g) (K''p)²= (6.00x10⁻³)²
The Kp of the reaction resulted by the sum will be: Kp = K'p*K''p
C(s) + CO₂(g) + 2Cl₂(g) ⇄ 2CO(g) + 2COCl₂(g)
Kp = 1.30x10¹⁴ * (6.00x10⁻³)²
Kp = 1.30x10¹⁴*3.60x10⁻⁵
Kp = 4.68x10⁹
Answer:
you would have to apply both of the low and high pressure together to make something?
Explanation:
Answer:
Hydrogenation
Explanation:
Look up the definition to confirm
Answer: 52.17%
Explanation:
Number of matches in the box = 46
Number of matches that lit on the first strike = 22
Number of matches that did not light on the first strike = 46 - 22 = 24
Therefore, the percentage of the matches in the box did not light on the first strike will be:
= (Number of matches that did not light on the first strike / Number of matches in the box) × 100
= 24/46 × 100
= 52.17%
Therefore, the percentage of the matches in the box that did not light on the first strike is 52.17%.
Answer:
Mole ratio for a compound
The chemical formula tells us the mole ratio.
CO2 = 1 CO2 molecule : 1 C atom : 2 O atoms.
Mole ratio for a reaction
The balanced chemical reactions tells us.
C12H22O11 + 12 O2 12 CO2 + 11 H2O
1 C12H22O11 molecule: 12 O2 molecules : 12 CO2
molecules : 11 H2O molecules.
Applications of the mole ratio concept
grams <--> moles <--> moles <--> grams
Explanation:
