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antoniya [11.8K]
3 years ago
11

Aluminum has a density of 2.70 g/mL. Calculate the mass (in grams) of a piece of aluminum having a volume of 381 mL . Express yo

ur answer to three significant figures.
Chemistry
2 answers:
laiz [17]3 years ago
4 0

Answer:

Mass ≈ 1030g (Three significant Figures)

Explanation:

We were given;

Density = 2.70 g/mL

Mass = ?

Volume = 381 mL

The relationship between all three parameters mentioned above is given by the formular below;

Density = Mass / Volume

Upon solving for Mass, we have;

Mass = Density * Volume

Substituting the respective values;

Mass = 2.7 * 381

Mass = 1028.7g

Mass ≈ 1030g (Three significant Figures)

BaLLatris [955]3 years ago
3 0
Multiply the volume by the density. 1 ml = 1 cm^3

1.11 g/cm^3 * 1 cm^3/mL * 386 mL = 428 g

All your units cancel out except for g which is what you would expect since you want units of mass.
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Please help!!<br> I don’t understand
laiz [17]
<h3>Answer:</h3>

150 g Si

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Use Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 3.2 × 10²⁴ atoms Si

[Solve] grams Si

<u>Step 2: Identify Conversions</u>

Avogadro's Number

[PT] Molar Mass of Si - 28.09 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                       \displaystyle 3.2 \cdot 10^{24} \ atoms \ Si(\frac{1 \ mol \ Si}{6.022 \cdot 10^{23} \ atoms \ Si})(\frac{28.09 \ g \ Si}{1 \ mol \ Si})
  2. [DA] Multiply/Divide [Cancel out units]:                                                            \displaystyle 149.266 \ g \ Si

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. Instructed to round to 2 sig figs.</em>

149.266 g Si ≈ 150 g Si

4 0
3 years ago
A mixture of propane and butane is burned with pure oxygen. The combustion products contain 46.7 mole% H2O. After all the water
wlad13 [49]

Answer:

28%

Explanation:

Basically, all o did was write the equations, balance it and solve for them. Also, at the place I stared, I used simultaneous equation to solve it. Multiplying by 8 and also 3.

It's a pretty straightforward question.

At the final step that's missing, I Did

(y)C3H8 = 2.8 / ( 2.8 + 7.1)

(y)C3H8 = 0.28

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daser333 [38]

Answer:

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Explanation:

that should be the answer

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