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lana [24]
3 years ago
13

Q5-P1 is 1.00atm and V1 is 3.00L. We've now changed the volume so P2 is 0.700atm. Use Boyle's Law, how much is V2? *Round your a

nswer to 3 significant digits.
Chemistry
2 answers:
Annette [7]3 years ago
7 0

Answer:

xccx

Explanation:

Tema [17]3 years ago
6 0
Answer: 4.29L




Explanation: use Boyle’s Law
P1V1=P2V2
(1.00)(3.00)=(0.700)(x)
Multiply 1.00•3.00
3.00=(0.700)(x)
Then divide .700 on each side to get x alone
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42.9 liters of hydrogen are collected over water at 76.0 °C and has a pressure of 294 kPa. What would the pressure (in kPa) of t
BabaBlast [244]

Answer:

494.1 kPa

Explanation:

Using the combined gas law equation;

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (kPa)

P2 = final pressure (kPa)

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question,

P1 = 294 kPa

P2 = ?

V1 = 42.9 liters

V2 = 22.8 liters

T1 = 76.0°C = 76 + 273 = 349K

T2 = 38.7°C = 38.7 + 273 = 311.7K

294 × 42.9/349 = P2 × 22.8/311.7

12612.6/349 = 22.8 P2/311.7

36.14 = 22.8P2/311.7

Cross multiply

36.14 × 311.7 = 22.8P2

11264.605 = 22.8P2

P2 = 11264.605 ÷ 22.8

P2 = 494.1 kPa

3 0
2 years ago
What is electron configuration of oxygen in its excited state​
timofeeve [1]

Answer:

1 {s}^{2} 2 {s}^{2} 2 {p}^{4}

OR

2 : 6

3 0
3 years ago
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Given that a 12.00 g milk chocolate bar contains 8.000 g of sugar, calculate the percentage of sugar present in 12.00 g of milk
neonofarm [45]
So in order for us to know the percentage of sugar present in a 12.00 g of milk chocolate, what we are going to do is that, we just have to divide 8 by 12 and multiply in by 100 and we get 66.67. Therefore, the percentage of sugar present in 12.00 g of milk chocolate bar is 66.67%. Hope this answers your question. Have a great day!
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3 years ago
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What element is a F-18 Atom
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Answer:

Sodium Fluoride F 18 Injection is a positron emitting radiopharmaceutical, no-carrier added.

Explanation:

Element Name Fluorine

Element Symbol F

Atomic Number 9

4 0
3 years ago
How is the law of conservation of matter represented in a chemical reaction?
blondinia [14]

Answer:

By balancing the chemical equation  

Explanation:

The Law of Conservation of Matter states that matter cannot be destroyed nor created.

That is, you must have the same amount of matter before and after a reaction.

Atoms are made of matter, so you must have the same number of each type of atom in the reactants as in the products. You must balance the equation.

Consider the reaction

2H₂ + O₂ ⟶ 2H₂O

You must have 2s in front of H₂ and H₂O to balance the atoms.

They give you four atoms of H and two atoms of O on each side of the arrow.

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