Sodium can achieve greater stability in its valence shell by

b)Elemental boron (as a gas) is produced in one industrial process by heating diboron trioxide with magnesium metal, also produc

dlinn [17]

<u>Answer:</u> The unbalanced chemical equation is written below.

<u>Explanation:</u>

Unbalanced chemical equation does not follow law of conservation of mass.

In an unbalanced chemical equation, total number of individual atoms on the reactant side will not be equal to the total number of individual atoms on the product side.

The chemical equation for the reaction of diboron trioxide and magnesium metal follows:

$B_2O_3(s)+Mg(s)\rightarrow B(g)+MgO(s)$

Hence, the unbalanced chemical equation is written above.

5 0

3 years ago

At room temperature (20°C} and pressure, the density of air is 1.189 g/L. An object will float in air if its density is less tha

Alekssandra [29.7K]

Explanation:

$Density =\frac{Mass}[Volume}$

Density of the air ,d= 1.189 g/L

(a) Density of the evacuated ball

Mass of the ball ,m = 0.12 g

Volume of the ball = $V=560 cm^3=560 ml=0.560 L$

$D =\frac{0.12 g}{0.560 L}=0.214 g/L$

D<d, teh evacuated ball will flaot in air.

(b) Density of the evacuated ball D = 0.214 g/L

Density of carbon dioxide gas = $d_1=1.830 g/L$

Mass of the carbon dioxide gas :

$1.830 g/L\times 0.560 L=1.0248 g$

Total density of filled ball with carbon dioxide gas:

$\frac{0.12 g+1.0248 g}{0.560 L}==2.044 g/L$

The ball filled with carbon dioxide will not float in the air because total density of filled ball is greater than the density of an air.

(c) Density of the evacuated ball D = 0.214 g/L

Density of hydrogen gas = $d_2=0.0899 g/L$

Mass of the hydrogen gas :

$1.830 g/L\times 0.560 L=0.050344 g$

Total density of filled ball with hydrogen gas:

$\frac{0.12 g+0.050344 g}{0.560 L}==0.3041 g/L$

The ball filled with hydrogen will float in the air because total density of filled ball is lessor than the density of an air.

(d) Density of the evacuated ball D = 0.214 g/L

Density of oxygen gas = $d_3=1.330 g/L$

Mass of the oxygen gas :

$1.330 g/L\times 0.560 L=1.7448 g$

Total density of filled ball with oxygen gas:

$\frac{0.12 g+1.7448 g}{0.560 L}=1.5442 g/L$

The ball filled with oxygen will not float in the air because total density of filled ball is greater than the density of an air.

(e) Density of the evacuated ball D = 0.214 g/L

Density of nitrogen gas = $d_4=1.165 g/L$

Mass of the nitrogen gas :

$1.165 g/L\times 0.560 L=0.6524 g$

Total density of filled ball with nitrogen gas:

$\frac{0.12 g+0.6524 g}{0.560 L}==1.3792 g/L$

The ball filled with nitrogen will not float in the air because total density of filled ball is greater than the density of an air.

f) Mass must be added to sink the ball = m

Density of ball > Density of the air ; to sink the ball.

$\frac{0.12g +m}{0.560L}>1.189 g/L$

m > 0.54584 g

For any case weight added to ball to make it sink in an air should be grater than the value of 0.54584 grams.

5 0

2 years ago

When the molecules of gases are heated, the average kinetic energy of the molecules increases,

serious [3.7K]

True is the answer to this

6 0

3 years ago

Two different compounds are formed by the elements nitrogen and oxygen. The first compound, compound P1, contains 64.17% by mass

xz_007 [3.2K]

Answer:

Explanation:

To solve the problem, we must know the kind of compounds we are dealing with.

For the first compound, P1 and second compound P2:

N O N O

Mass percent 64.17 35.73 47.23 52.79

Atomic mass 14 16 14 16

Number of

moles 64.17/14 35.73/16 47.23/14 52.79/16

4.58 2.23 3.37 3.30

Simplest

ratio 4.58/2.23 2.23/2.23 3.37/3.30 3.3/3.3

2 1 1 1

P1 compound is N₂O

P2 compound is NO

These are the compounds,

In N₂O = 28:16

NO = 14:16

This is the ratio of nitrogen to a fixed mass of oxygen for the two compounds.

7 0

2 years ago

Two liters of hydrogen gas are stored at a

Tju [1.3M]

Answer:

the volume will expand

Explanation:

gas under pressure contracts, and expands with a lesser pressure

6 0

2 years ago