Answer:
a) 2NaOH+H2SO4→Na2SO4+2H2O2NaOH+H2SO4→Na2SO4+2H2O
b) Số phân tử NaOH : Số phân tử H2SO4 = 2:1
Số phân tử NaOH : Số phân tử Na2SO4 = 2:1
Số phân tử NaOH : Số phân tử H2O = 2:2
Explanation:
Three sig figs, the leading zeros are not sig figs
Explanation:
Using ethyl 3-methylbutanoate as your only source of carbon and using any other reagents necessary, propose a stepwise synthesis for the following conversion.
I need help drawing the product formed in step three.
Thanks!
The answer is A. It is an alkyn. There is a triple bond