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aleksandr82 [10.1K]
2 years ago
8

Sound enters the ear, travels through the auditory canal, and reaches the eardrum. The auditory canal is approximately a tube op

en at only one end. The other end is closed by the eardrum. A typical length for the auditory canal in an adult is about 3.1 cm. The speed of sound is 336 m/s. What is the fundamental frequency of the canal
Physics
1 answer:
Juliette [100K]2 years ago
7 0

Answer:

The fundamental frequency of can is 2.7 kHz.                          

Explanation:

Given that,

A typical length for the auditory canal in an adult is about 3.1 cm, l = 3.1 cm

The speed of sound is, v = 336 m/s

We need to find the fundamental frequency of the canal. For a tube open at only one end, the fundamental frequency is given by :

f=\dfrac{v}{4l}\\\\f=\dfrac{336}{4\times 3.1\times 10^{-2}}\\\\f=2709.67\ Hz\\\\f=2.7\ kHz

So, the fundamental frequency of can is 2.7 kHz. Hence, this is the required solution.

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Answer:

 F = 5226.6 N

Explanation:

To solve a lever, the rotational equilibrium relation must be used.

We place the reference system on the fulcrum (pivot point) and assume that the positive direction is counterclockwise

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In this case the length of the lever is L = 5m, t the distance desired by the fulcrum from the weight to be lifted is

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therefore the distance to the applied force is

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we clear from the equation

          F = W d₂ / d₁

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we calculate

      F = 800 9.8 2/3

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