Answer:
#Molecules XeF₆ = 2.75 x 10²³ molecules XeF₆.
Explanation:
Given … Excess Xe + 12.9L F₂ @298K & 2.6Atm => ? molecules XeF₆
1. Convert 12.9L 298K & 2.6Atm to STP conditions so 22.4L/mole can be used to determine moles of F₂ used.
=> V(F₂ @ STP) = 12.6L(273K/298K)(2.6Atm/1.0Atm) = 30.7L F₂ @ STP
2. Calculate moles of F₂ used
=> moles F₂ = 30.7L/22.4L/mole = 1.372 mole F₂ used
3. Calculate moles of XeF₆ produced from reaction ratios …
Xe + 3F₂ => XeF₆ => moles of XeF₆ = ⅓(moles F₂) = ⅓(1.372) moles XeF₆ = 0.4572 mole XeF₆
4. Calculate number molecules XeF₆ by multiplying by Avogadro’s Number (6.02 x 10²³ molecules/mole)
=> #Molecules XeF₆ = 0.4572mole(6.02 x 10²³ molecules/mole)
= 2.75 x 10²³ molecules XeF₆.
Answer:
is the symbol for an oxide ion
Answer:
How many grams of CCL4 were formed? 116.9 g
How many grams of Cl2 reacted with the CH4? 243.8 g
Explanation:
First we need to know the molar mass for every element or compound in the reaction:

Now we proceed to calculate the amount of moles produced, per product:

To calculate the mass of chlorine we just need to make a mass balance:

Answer: Chlorine gas is produced when sulfuric acid is mixed with chlorine bleach.
Explanation: This reaction is a function of the change in pH of the solution from alkaline to acidic combined with the strong oxidant properties of hypochlorous acid.
<h2><u><em>
Make sure to reword this in your words!!!</em></u></h2>