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Mashcka [7]
3 years ago
15

Madison was reading about force in her science textbook and came across a lab that she wanted to do. Madison took detailed notes

of the lab produce to use the next day what specific process is Madison demonstrating by conducting the experiment
Chemistry
1 answer:
Aneli [31]3 years ago
4 0

Answer:

what i dont understand the question

Explanation:

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Suppose we have 100 g of each of the following substances. Which sample contain the greatest number of moles (F.W. = Formula Wei
Sindrei [870]

Answer:

100 g of water has the highest number of moles

Explanation:

Recall that the number of moles is obtained as given mass/formula weight

For HCl;

number of moles = 100g/36.5g/mol = 2.7 moles

For H2O;

number of moles = 100g/18g/mol = 5.5 moles

For MgCO3

number of moles = 100g/84.3 g/mol = 1.2 moles

For AlCl3

number of moles = 100g/133.3g/mol = 0.75 moles

For NaCl

number of moles = 100g/58.4 g/mol = 1.7 moles

3 0
3 years ago
Wsp im fisdes once again hiiiii
Diano4ka-milaya [45]

Answer:

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Explanation:

6 0
3 years ago
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How much energy must a 10 gram block of ice gain in order to melt ?
Minchanka [31]

Answer:

the answer is 10 times

Explanation:

because it takes 10 times as much energy -3330 j - to melt 10.0 grams of ice.

8 0
2 years ago
How many moles of hydrogen gas will form 1.35 L of a 2.75 M Hcl solution reacts?
weeeeeb [17]
<span>1.86 moles of hydrogen gas. Since what the HCl is reacting with hasn't been mentioned, I'll assume zine. In that case, the balanced reaction is Zn + 2HCl ==> ZnCl2 + H2 So for every 2 moles of HCl used, 1 mole of hydrogen gas will be generated. So let's figure out how many moles of HCl we have and then divide by 2. Molarity is defined as moles/liter. So a 2.75 M HCl solution has 2.75 moles of HCl per liter. So the total number of moles we have is: 2.75 mole/L * 1.35 L = 3.7125 mol And since we get 1 mole H2 per mole of HCl, we get: 3.7125 mol / 2 = 1.85625 mol Rounding to 3 significant figures gives us 1.86 moles of hydrogen gas.</span>
3 0
3 years ago
Use this oxidation-reduction reaction to answer questions about half-reactions:
Advocard [28]

Answer:

N, O, R

Explanation:

Thanks for answering bro, you saved me

5 0
2 years ago
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