0.77 m/s2 directed 35° south of west
net force = (-17,-12)
net force = mass * acceleration
(-17,-12) = 27 * (x-acceleration,y-acceleration)
(x-acceleration,y-acceleration) = (-17/27,-12/27) = (-0.629629629..., -0.444...)
angle of acceleration = tan^-1 (-0.444.../-0.629629...) = 35.21759 degrees below negative x-axis.
magnitude of acceleration = sqrt((-0.629629...)^2 + (-0.444...)^2) = 0.77069 (5dp)
Answer:
E = q V B describes the electric field induced
E Proportional to V B
while the magnet is pushed into the coil the induced field (B) will increase (consider 1 turn of the coil)
If V is constant the E-field will increase due to increasing B and the galvanometer will deflect accordingly
When V drops to zero the deflection must again be zero
So one would see a blip due to the deflection of the galvanometer
Note that as V increases the galvanometer will deflect one way and then as V drops to zero the deflection will be opposite (drop to zero when V is zero)
B always increases to a constant value because of the properties of the magnet.
Net force = (mass) x (acceleration)... that’s Newton’s 2nd law of motion.
Net force = (15kg) x (10 m/s squared)
Net force = 150 Newtons.
Answer:
I font now but I think its 2.0 + 78 w -60
