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Alexeev081 [22]
3 years ago
14

The mayor knows the area needed for a flower garden in the park. She wants the base to be a certain length. How can she determin

e the necessary height to get the correct area of the flower garden? Explain.
Mathematics
2 answers:
DiKsa [7]3 years ago
6 0

Answer:The formula for the area of a parallelogram is A = bh, and the formula for area of a triangle is A = 1/2bh. Since a triangle is half of the area of a parallelogram with the same base and height, the only difference in the formula is 1/2.

that is the sample answer hope that helped good luck ✌️

ikadub [295]3 years ago
5 0

Answer:

First, she starts with the formula for area for the specific shape in the problem. Then, substitute the area and the base into the formula. Finally, she can solve the resulting equation for the height.

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50 points! I understand A. and B. but I would really appreciate help with C.
FromTheMoon [43]

Answer:

51.72\text{ cells per hour}

Step-by-step explanation:

So, the function, P(t), represents the number of cells after t hours.

This means that the derivative, P'(t), represents the instantaneous rate of change (in cells per hour) at a certain point t.

C)

So, we are given that the quadratic curve of the trend is the function:

P(t)=6.10t^2-9.28t+16.43

To find the <em>instanteous</em> rate of growth at t=5 hours, we must first differentiate the function. So, differentiate with respect to t:

\frac{d}{dt}[P(t)]=\frac{d}{dt}[6.10t^2-9.28t+16.43]

Expand:

P'(t)=\frac{d}{dt}[6.10t^2]+\frac{d}{dt}[-9.28t]+\frac{d}{dt}[16.43]

Move the constant to the front using the constant multiple rule. The derivative of a constant is 0. So:

P'(t)=6.10\frac{d}{dt}[t^2]-9.28\frac{d}{dt}[t]

Differentiate. Use the power rule:

P'(t)=6.10(2t)-9.28(1)

Simplify:

P'(t)=12.20t-9.28

So, to find the instantaneous rate of growth at t=5, substitute 5 into our differentiated function:

P'(5)=12.20(5)-9.28

Multiply:

P'(5)=61-9.28

Subtract:

P'(5)=51.72

This tells us that at <em>exactly</em> t=5, the rate of growth is 51.72 cells per hour.

And we're done!

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