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7nadin3 [17]
3 years ago
9

Given: Which additional congruence statement could you use to prove that ∆BJK ≅ ∆CFH by the HL Theorem? ∠BJK ≅ ∠CFH ∠B ≅ ∠C

Mathematics
2 answers:
siniylev [52]3 years ago
5 0

Answer:  JK=FH                            

Step-by-step explanation:

earnstyle [38]3 years ago
3 0

Answer:

∠BJK ≅ ∠CFH

Step-by-step explanation:

∆BJK ≅ ∆CFH then we say ∠BJK ≅ ∠CFH

Only when we say ∠BJK ≅ ∠CFH we can say (expand) and speak of lengths by comparing two of each ∠BJA ≅ ∠AFC whilst ∠BK≅ ∠ HC then repeat with∠BKJ  ≅ ∠CHF etc.

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David wants to make a box plot showing histeam's points for the year. The median score was 7, first quartile was 4, and third qu
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A dot above 7, 4, 10, 2, and 20. Draw a box around the median, first quartile, and and the third quartile. Then connect the box to the minimum and maximum by drawing a line. Should look like this:

8 0
3 years ago
Solve for x. −5(x−4)=−30
Readme [11.4K]
Let's solve your equation step-by-step.<span><span>−<span>5<span>(<span>x−4</span>)</span></span></span>=<span>−<span>30

</span></span></span>Step 1: Simplify both sides of the equation.<span><span>−<span>5<span>(<span>x−4</span>)</span></span></span>=<span>−30</span></span>
<span>Simplify: (Show steps)</span><span><span><span>−<span>5x</span></span>+20</span>=<span>−<span>30

</span></span></span>Step 2: Subtract 20 from both sides.<span><span><span><span>−<span>5x</span></span>+20</span>−20</span>=<span><span>−30</span>−20</span></span><span><span>−<span>5x</span></span>=<span>−<span>50

</span></span></span>Step 3: Divide both sides by -5.<span><span><span>−<span>5x</span></span><span>−5</span></span>=<span><span>−50</span><span>−5</span></span></span><span>x=<span>10

</span></span>Answer:<span>x=<span>10</span></span>
8 0
3 years ago
Read 2 more answers
Solve each of the following quadratic equations<br><br> 3x=0.5x^2<br><br><br> 0=5x^2-2x+6
UNO [17]

<u>Question 1</u>

<u />3x=0.5x^{2}\\\\6x=x^{2} \\ \\ x^{2}-6x=0 \\ \\ x(x-6)=0 \\ \\ \boxed{x=0, 6}

<u>Question 2</u>

<u />0=5x^{2}-2x+6 \\ \\ x=\frac{2 \pm \sqrt{(-2)^{2}-4(5)(6)}}{2} \\ \\ x=\frac{2 \pm \sqrt{-116}}{10} \\ \\ x=\frac{2 \pm 2i\sqrt{29}}{10} \\ \\ \boxed{x=\frac{1 \pm i\sqrt{29}}{5}}

6 0
2 years ago
Help help help math math
denpristay [2]

Answer:

Function

Step-by-step explanation:

Hope it help !!

3 0
2 years ago
sum of two numbers is 39. the greater number is 7 more than the smaller number. ( set up an equation )
pochemuha
Let x be the unknown number

2x +7 = 39

2x+7-7 = 39-7

2x = 32

2x/2 = 32/2

x=16

You use the balance method to solve. First, you cancel the +7 by subtracting the 7 ON BOTH SIDES to balance the equation.. After that, you are left with 2x, where you will need to isolate the x by dividing by 2 ON BOTH SIDES to balance it.

Hope this helps
3 0
3 years ago
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