Question

Given: Which additional congruence statement could you use to prove that ∆BJK ≅ ∆CFH by the HL Theorem? ∠BJK ≅ ∠CFH ∠B ≅ ∠C

Answer 1

Answer:  JK=FH                            

Step-by-step explanation:

Answer 2

Answer:

∠BJK ≅ ∠CFH

Step-by-step explanation:

∆BJK ≅ ∆CFH then we say ∠BJK ≅ ∠CFH

Only when we say ∠BJK ≅ ∠CFH we can say (expand) and speak of lengths by comparing two of each ∠BJA ≅ ∠AFC whilst ∠BK≅ ∠ HC then repeat with∠BKJ  ≅ ∠CHF etc.