Given: Which additional congruence statement could you use to prove that ∆BJK ≅ ∆CFH by the HL Theorem? ∠BJK ≅ ∠CFH ∠B ≅ ∠C
2 answers:
You might be interested in
The first part of the answer can be found by finding the GCF between 15 and 25. 15 is divisible by 1, 3, 5, and 15. 25 is divisible by 1, 5, and 25. You can see that their GCF is 5. Next, you need to look at the variables. The first monomial has a, b, and 
. The second monomial has 
, b, and c. They each have at least one a, one b, and one c, so those will be in the GCF (abc). If you put that together with the 5, you get that the GCF is 5abc.