The mass of water in the tank, given the data from the question is 549594 g
<h3> Description of mole </h3>
The mole of a substance is related to it's mass and molar mass according to the following equation:
Mole = mass / molar mass
<h3>How to determine the mass of water in the tank</h3>
From the question given above, the following data were obtained:
- Mole of water = 30533 moles
- Molar mass of water = 18 g/mol
- Mass of water = ?
The mass of the water can be obtained as follow:
Mass = mole × molar mass
Mass of water = 30533 × 18
Mass of water = 549594 g
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Answer:
1.08 grams
Explanation:
first, we need to find the number of moles
we divide 12.1/22.4=0.54 moles
we multiply the number of moles with the molecular mass 0.54x2=1.08g
+5
Explanation:
The given radical is PO₄³⁻
To solve this problem, we need to understand what oxidation number entails.
The extent of the oxidation of each atom is expressed by the oxidation number.
Here are some rules for assigning them:
- Elements in an uncombined state or elements that combines with one another, their oxidation number is zero.
- The charge on an ion is its oxidation number
- In an neutral compound, algebraic sum of all the oxidation numbers of all atoms is zero.
- In a radical, the algebraic sum of all the oxidation numbers of the ions is equal to the charge on them.
Oxygen is known to have an oxidation number of -2;
PO₄³⁻
P + 4(-2) = -3
P -8 = -3
P = -3 + 8 = +5
The charge on phosphorus is +5
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Answer:
10437calories
Explanation:
The following data were obtained from the question given:
M = 347.9g
C = 4.2J/g°C
T1 = 25°C
T2 = 55°C
ΔT = 55 — 25 = 30°C
Q =?
Q = MCΔT
Q = 347.9 x 4.2 x 30
Q = 43835.4J
Converting this to calories, we obtained the following:
4.2J = 1 calorie
43835.4J = 43835.4/ 4.2 = 10437calories
