Answer:The product and reactants reach a final, unchanging level.
Answer:
a) 157.5 grams of aluminum.
b) 1 mol
c) 9 g
Explanation:
The reaction is :

As per balanced equation
a) 3 moles of hydrogen will be produced from two moles of aluminium.
The atomic mass of aluminium = 27
therefore
3X2 grams of hydrogen is produced from 2 X 27 grams of Al
1 gram of hydrogen will be produced from
g
therefore 17.5 will be produced from = 9X 17.5 = 157.5 grams of aluminum.
b) as per balanced equation three moles or six gram of hydrogen is produced from 6 moles of NaOH.
Therefore 1 g of hydrogen will be produced from =
or 1 gram will be prepared from = 1 mole
c) from balanced equation three moles are produced from two moles of Al (27X2 = 54 g).
thus from 54 grams gives 6 grams of hydrogen
1 grams will give =
Answer:

Explanation:
We are asked to find the density of a metal. Density is the mass per unit volume. It is calculated by dividing the mass by the volume.

The mass of the metal sample is 24.64 grams and the volume is 5.91 milliliters. We can substitute these values into the formula.

Divide.

The mass measurement has 4 significant figures the volume measurement has 3 significant figures. Our answer for density must match the least number of significant figures, which is 3.
For the number we calculated, that is the hundredth place. The 9 in the thousandth place tells us to round the 6 up to a 7.

The density of this metal is approximately <u>4.17 grams per milliliter.</u>
Data Given:
% w/w = 5 %
Solution weight = 1500 g
Solute weight = ?
Formula Used:
% w/w = (Mass of Solute / Mass of Solution) × 100
Solving for Mass of Solute,
Mass of Solute = (% w/w × Mass of Solution) ÷ 100
Mass of Solute = (5 × 1500 g) ÷ 100
Mass of Solute = 75 g K₂SO₄