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Mekhanik [1.2K]
3 years ago
13

If you need some points and are good at science help!

Chemistry
2 answers:
fomenos3 years ago
8 0

Answer:

2, 3 They are closest to the equator, and the equator marks to hottest places on earth.

Explanation:

I hope this helps you.

bonufazy [111]3 years ago
6 0

Answer:

region 2 and region 3

Explanation:

you can tell by the color of the land my friends^^

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What is the molecular formula of a compound containing 89% cesium (Cs) and 11% oxygen (O) with a molar mass = 298 g/mol?
Maurinko [17]
M(Cs)=133 g/mol
M(O)=16 g/mol
M(CsxOy)=298 g/mol
w(Cs)=0.89
w(O)=0.11

CsxOy

x=M(CsxOy)w(Cs)/M(Cs)
x=298*0.89/133=2

y=M(CsxOy)w(O)/M(O)
y=298*0.11/16=2

Cs₂O₂  cesium peroxide
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3 years ago
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Question # 10
satela [25.4K]
The answer should be D, cells can only create an identical copy of the original cell.
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3 years ago
Select the properly written and balanced equation for the following chemical reaction: Sodium metal and an aqueous solution of m
Setler [38]

Answer:2Na(s)+MgI_2 (aq)\rightarrow 2NaI(aq)+Mg(s)

Explanation: The chemical reaction is written by writing down the chemical formulas of the reactants on the left hand side and the chemical formulas of products on the right hand side separated by a right arrow.

This is a single displacement reaction in which a more reactive element displaces the less reactive element from its salt solution. Thus sodium is more reactive than Mg and thus displaces it from MgI_2.

2Na(s)+MgI_2 (aq)\rightarrow 2NaI(aq)+Mg(s)

The number of atoms of each element must be same on both sides of the reaction so as to follow the law of conservation of mass. Thus the equation is balanced.

5 0
3 years ago
What is the formula of nitrous acid?
Charra [1.4K]
That formula would be HNO2
5 0
3 years ago
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The compound Xe(CF3)2 decomposes in afirst-order reaction to elemental Xe with a half-life of 30. min.If you place 7.50 mg of Xe
Irina-Kira [14]

Answer:

t=147.24\ min

Explanation:

Given that:

Half life = 30 min

t_{1/2}=\frac{\ln2}{k}

Where, k is rate constant

So,  

k=\frac{\ln2}{t_{1/2}}

k=\frac{\ln2}{30}\ min^{-1}

The rate constant, k = 0.0231 min⁻¹

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

Given that:

The rate constant, k = 0.0231 min⁻¹

Initial concentration [A_0] = 7.50 mg

Final concentration [A_t] = 0.25 mg

Time = ?

Applying in the above equation, we get that:-

0.25=7.50e^{-0.0231\times t}

750e^{-0.0231t}=25

750e^{-0.0231t}=25

x=\frac{\ln \left(30\right)}{0.0231}

t=147.24\ min

6 0
3 years ago
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