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Mekhanik [1.2K]
3 years ago
13

If you need some points and are good at science help!

Chemistry
2 answers:
fomenos3 years ago
8 0

Answer:

2, 3 They are closest to the equator, and the equator marks to hottest places on earth.

Explanation:

I hope this helps you.

bonufazy [111]3 years ago
6 0

Answer:

region 2 and region 3

Explanation:

you can tell by the color of the land my friends^^

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Which of the following describes a reaction that reaches equilibrium?
alexandr1967 [171]

Answer:The product and reactants reach a final, unchanging level.

8 0
2 years ago
6 NaOH + 2 Al ???? 2 Na3AlO3 + 3 H2 How much aluminum is required to produce 17.5 grams of hydrogen? How many moles of NaOH are
ANTONII [103]

Answer:

a) 157.5 grams of aluminum.

b) 1 mol

c) 9 g

Explanation:

The reaction is :

6 NaOH + 2Al ---> 2 Na_{3}AlO_{3} + 3H_{2}

As per balanced equation

a) 3 moles of hydrogen will be produced from two moles of aluminium.

The atomic mass of aluminium = 27

therefore

3X2 grams of hydrogen is produced from 2 X 27 grams of Al

1 gram of hydrogen will be produced from \frac{2X27}{3X2}= 9g

therefore 17.5 will be produced from = 9X 17.5 = 157.5 grams of aluminum.

b) as per balanced equation three moles or six gram of hydrogen is produced from 6 moles of NaOH.

Therefore 1 g of hydrogen will be produced from =\frac{6}{6}

or 1 gram will be prepared from = 1 mole

c) from balanced equation three moles are produced from two moles of Al (27X2 = 54 g).

thus from 54  grams gives 6 grams of hydrogen

1 grams will give = \frac{54X1}{6}= 9 g

7 0
3 years ago
Read 2 more answers
A sample of metal has a mass of 24.64 g, and a volume of 5.91 mL. What is the density of this metal?
dlinn [17]

Answer:

\boxed {\boxed {\sf 4.17 \ g/mL}}

Explanation:

We are asked to find the density of a metal. Density is the mass per unit volume. It is calculated by dividing the mass by the volume.

\rho= \frac{m}{v}

The mass of the metal sample is 24.64 grams and the volume is 5.91 milliliters. We can substitute these values into the formula.

  • m= 24.64 g
  • v= 5.91 mL

\rho=\frac{24.64 \ g }{5.81 \ mL}

Divide.

\rho= 4.169204738 \ g/mL

The mass measurement has 4 significant figures the volume measurement has 3 significant figures. Our answer for density must match the least number of significant figures, which is 3.

For the number we calculated, that is the hundredth place. The 9 in the thousandth place tells us to round the 6 up to a 7.

\rho \approx 4.17 \ g/mL

The density of this metal is approximately <u>4.17 grams per milliliter.</u>

3 0
2 years ago
How many grams of k2so4 would you need to prepare 1500 g of 5.0% k2so4 solution?
son4ous [18]
Data Given:
                                  % w/w  =  5 %

                    Solution weight  =  1500 g

                       Solute weight  =  ?

Formula Used:
                            % w/w  =  (Mass of Solute / Mass of Solution) × 100

Solving for Mass of Solute,
         
                       Mass of Solute  =  (% w/w × Mass of Solution) ÷ 100

                       Mass of Solute  =  (5 × 1500 g) ÷ 100

                       Mass of Solute  =  75 g K₂SO₄
5 0
3 years ago
How many grams of molecular chlorine will be required to completely react with 0.0223 moles of sodium iodide according to the fo
Alecsey [184]

Answer: a

aa

Explanation: a

aaa

8 0
2 years ago
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