Oxygen and glucose that’s all I know
Answer:
0.342 m
Explanation:
From the question given above, the following data were obtained:
Mass of NaBr = 14.57 g
Mass of water = 415 g
Molar mass of NaBr = 102.89 g/mol
Molality of NaBr =?
Next, we shall determine the number of mole in 14.57 g of NaBr. This can be obtained as follow:
Mass of NaBr = 14.57 g
Molar mass of NaBr = 102.89 g/mol
Mole of NaBr =?
Mole = mass / molar mass
Mole of NaBr = 14.57 / 102.89
Mole of NaBr = 0.142 mole
Next, we shall convert 415 g of water to kg. This can be obtained as follow:
1000 g = 1 Kg
Therefore,
415 g = 415 g × 1 Kg / 1000 g
415 g = 0.415 Kg
Thus, 415 g is equivalent to 0.415 Kg.
Finally, we shall determine Molality of the solution as follow:
Mole of NaBr = 0.142 mole
Mass of water = 0.415 Kg
Molality of NaBr =?
Molality = mole / mass of water in Kg
Molality of NaBr = 0.142 / 0.415
Molality of NaBr = 0.342 m
Therefore, the molality of NaBr solution is 0.342 m.
If the magnetic toy trains are opposite charges, they will attract each other and collide however if the trains are of the same charge, they will oppose each other. This is because electrostatic force (the opposite forces so + and -) attract opposite charges
Hope that helps :)
Answer:
2-
Explanation:
The dichromate ion is the part of the compound that looks like: Cr2O7.
Our current compound is Ag2CrO7. The “2” on Ag indicates that there are two atoms of Ag in this compound, while the absence of a number on Cr2O7 indicates that there is only one atom of Cr2O7.
In order to maintain balance within the compound, the product of one of the ion’s charge with its atom amount must be equivalent to the product of the other ion’s charge with its atom amount. This is because the charges will ultimately add up to 0, which is the neutral substance we want.
Here, we know the “atom amount” of Ag is 2 and that its charge is 1+. So that’s 2 * 1 = 2. We also know that the “atom amount” of Cr2O7 is 1 and that its charge is x, for example. Then: x * 1 + 2 = 0. That means x = -2.
Thus, the charge on the dichromate ion is 2-.
