1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
timurjin [86]
4 years ago
12

If you push on an object that has a mass of 400 kg and it accelerates at 4 m/s2, what would the acceleration (a) be if the mass

was reduced to 1/4 as much?
(Hint: Instead of plugging 400 kg into the equation, plug 100 kg into the equation as the mass but keep the force at 1,600 N.)

a
1/4 m/s2

b
16 m/s2

c
8 m/s2

d
4 m/s2
Physics
1 answer:
Temka [501]4 years ago
6 0

Answer:

b  16 m/s².

Explanation:

Hello.

In this case, the force exerted to the mass of 400 kg at an acceleration of 4 m/s² is:

F=400kg*4m/s^2=1600N

Now, since the mass is decreased to 100 kg (1/4 of 400 kg), and the force remain the same, the new acceleration should be:

a=\frac{F}{m}=\frac{1600kg*m/s^2}{100kg}\\  \\a=16m/s^2

Thus, the answer is b  16 m/s².

Best regards.

You might be interested in
One ring of radius a is uniformly charged with charge +Q and is placed so its axis is the x-axis. A second ring with charge –Q i
kati45 [8]

Answer:

The force exerted on an electron is 7.2\times10^{-18}\ N

Explanation:

Given that,

Charge = 3 μC

Radius a=1 m

Distance  = 5 m

We need to calculate the electric field at any point on the axis of a charged ring

Using formula of electric field

E=\dfrac{kqx}{(a^2+x^2)^{\frac{3}{2}}}\hat{x}

E_{1}=\dfrac{kqx}{(a^2+x^2)^{\frac{3}{2}}}\hat{x}

Put the value into the formula

E_{1}=\dfrac{9\times10^{9}\times3\times10^{-6}\times5}{(1^2+5^2)^{\frac{3}{2}}}

E_{1}=1.0183\times10^{3}\ N/C

Using formula of electric field again

E_{2}=\dfrac{kqx}{(a^2+x^2)^{\frac{3}{2}}}\hat{x}

Put the value into the formula

E_{2}=\dfrac{9\times10^{9}\times(-3\times10^{-6})\times5}{((0.5)^2+5^2)^{\frac{3}{2}}}

E_{2}=-1.064\times10^{3}\ N/C

We need to calculate the resultant electric field

Using formula of electric field

E=E_{1}+E_{2}

Put the value into the formula

E=1.0183\times10^{3}-1.064\times10^{3}

E=-0.045\times10^{3}\ N/C

We need to calculate the force exerted on an electron

Using formula of electric field

E = \dfrac{F}{q}

F=E\times q

Put the value into the formula

F=-0.045\times10^{3}\times(-1.6\times10^{-19})

F=7.2\times10^{-18}\ N

Hence, The force exerted on an electron is 7.2\times10^{-18}\ N

8 0
3 years ago
What happens when calcium reacts with chlorine?
choli [55]

Answer: They create calcuim chloride, CaCl2

7 0
3 years ago
Calculate the pressure on a man’s foot when a woman who weighs 520 N steps on his foot with her heel which has an area of 0.001
Vinvika [58]

Answer:

520000  or 520000 pa

Force = 520N

Area of contact = 0.001

Pressure: 520000 or 520000

6 0
3 years ago
What will be the effect on each of these objects, the bowling ball and the baseball?
Nastasia [14]
What effect man there are a million effects the only one that arent true are fusion or fission and magnetism unless that bowling ball is iron 
7 0
3 years ago
Select all the statements regarding electric field line drawings that are correct.
Sophie [7]

Answer:

All statement are correct.

Explanation:

1. Electric field lines are the same thing as electric field vectors, electric field are mathematically vectors quantity. These vectors point in the direction in which a positive test charge would move.

2.  Electric field line drawings allow you to determine the approximate direction of the electric field at a point in space. Yes it is correct tangent drawn at any point on these lines gives the direction of electric filed at that point.

3. The number of electric field lines that start or end at a charged particle is proportional to the magnitude of charge on the particle, is a correct statement.

4.The electric field is strongest where the electric field lines are close together, again a correct statement as relative closeness of field lines indicate a stronger strength of electric field.

Hence we can say that all the statement are correct.

7 0
3 years ago
Other questions:
  • What is the speed of a wave with a wavelength of 0.60 m and frequency of 240 Hz
    13·1 answer
  • explain how an earth wire in an appliance can help to prevent damage or injury to users when a fault occurs in the appliance.
    8·1 answer
  • Why does a comet's tail point away from the Sun? 1Choice 1 The solar wind blows the tail away from the Sun. 2 It is being pulled
    10·1 answer
  • The back shelf of a car has a physics textbook on it. The coefficient of static friction of 0.44 between the book and the surfac
    11·1 answer
  • A boy rides a bike 56 meters. It takes him 8 seconds. What is his speed?
    8·2 answers
  • A crate resting on a rough horizontal floor is to be moved horizontally. The coefficient of static friction is 0.36. To start th
    12·1 answer
  • What is the fault-current circuit breaker? Describe its function.
    10·2 answers
  • - A wooden crate that measures 2.0 m long and 0.40 m wide rests on
    9·1 answer
  • Part a a calorimeter consists of an aluminum cup inside of an insulated container. The cup is weighed on a top-loading balance a
    11·1 answer
  • The following sentences describe chemical reactions. For each one, enter the skeletal structure of the reaction in the text box.
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!