Answer:
a = = 37.2V
b = 13.39MJ
Explanation:
Given that
L = 170 × 10³
r = d/2
= 10cm / 2 = 5 cm
current I = 100A
we are to find the potential drop across the cable
so, we can use ohm’s law
V = IR = I (ρL/A)
ρ = resistivity of the copper
= 1.72 × 10⁻⁸ Ω.m
A = πr²
V = I(ρL/πr²)
= 100 (( 1.72 × 10⁻⁸ * 170 × 10³) / ( π * 0.05²))
= 37.2V
(b)
Energy (loss) = Pt
Enery (loss) = IVt
3600s per hour
= (100A)(37.2V)(3600s)
= 13.39MJ
Answer:
An ion.
Explanation:
Atoms can gain or lose electrons and become ions, which are atoms that have a positive or negative charge, because they have unequal numbers of protons and electrons.
Answer:
There are 6 electrons in the outermost shell.
Explanation:
Sulphur is a non-mettalic element which is in the period 3 and group .6on the periodic table. It has an atomic number of 16 and a Mass number of 32. Atomic number tells you the number of electrons in an electrically neutral atom. It has the electronic configuration of 1s2 2s2 2p6 3s2 3p4.
The orbitals have a formula 2n^2 where n = 0, 1, 2, 3 etc.
In the shells, n = 1 so there are 2 electrons. For n = 2, 2*(2)^2 = 8 electrons. So, 16 - (8 + 2) = 6 electrons in the 3 shell (outermost shell)
Therefore from the electronic confriguration above, there are 6 electrons in the outermost shell.
Answer:
Half
Explanation:
Given that:
- radial distance of satellite from the earth,
Now, if the satellite is moved to a distance 
<u>We have the mathematical expression for the potential energy fue to gravitational field as:</u>
...................(1)
where:
M = mass of earth
m = mass of satellite
R = radial distance of satellite
<u>Now from eq. (1) initially we have:</u>
<u>after the satellite is moved, we have:</u>
which is half of the initial condition.
