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Nadya [2.5K]
3 years ago
8

Learning to ride a bike, is what kind of learning?

Physics
1 answer:
Oksanka [162]3 years ago
5 0
Learning to do something or like riding your bike is a physical learning also known as kinesthetic and its because you prefer using your body for the sense of touch. Hope it helps
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What can be inferred when an atom is electrically charged?
Elena-2011 [213]

When an atom becomes electrically charged the number of electrons or protons stops and they are not equal again. The "extra" electron or proton is not balanced by something inside the atom any longer and it starts attracting itself to othet protons or electrons in other atoms.

<h3>What is atomic structure?</h3>

An atomic structure comprises of positively charged nucleus which is surrounded by negatively charged particles called electron and neutron which is neutral charged.

Unlike charges attract each other while like charges repel each other.

Therefore, When an electron is fully charged, the number of electrons will stop to be unequal again.

Learn more about Atomic charge here.

brainly.com/question/18102056

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2 years ago
The type of energy that depends on position is called
attashe74 [19]
The type of energy that depends on position is called
kinetic energy
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3 years ago
I just need the answer to number 1 (with work please) <br> (Newton’s Second Law)
Valentin [98]

Answer:

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Explanation:

I been rereading this and I can't solve it lemme go ask people in ma house real quick

8 0
3 years ago
Based on experimental observations, the acceleration of a particle is defined by the relation a = -(0.1 + sin x/b), where a and
Fiesta28 [93]

Answer:

Velocity,v = 0.323 m/s

Explanation:

The acceleration of a particle is given by :

a=-(0.1+sin\dfrac{x}{b})

b = 0.8 m when x = 0

Since, a=v\dfrac{dv}{dx}  

v\dfrac{dv}{dx}=-(0.1+sin\dfrac{x}{b})  

\int{v.dv}=\int{-(0.1+sin\dfrac{x}{b})}.dx

\dfrac{v^2}{2}=-[0.1x-0.8cos\dfrac{x}{0.8}]+c

At x = 0, v = 1 m/s

\dfrac{1}{2}=0.8+c

c=-0.3

\dfrac{v^2}{2}=-[0.1x-0.8cos\dfrac{x}{0.8}]-0.3

At x = -1 m

\dfrac{v^2}{2}=-0.1(-1)+0.8cos\dfrac{(-1)}{0.8}-0.3

{v^2}=0.1045

v = 0.323 m/s

So, the velocity of the particle is 0.323 m/s. Hence, this is the required solution.

8 0
3 years ago
A material that provides little or no resistance to the flow of electric current is called a/an
GarryVolchara [31]
Conductor .......................
3 0
3 years ago
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