1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mars2501 [29]
3 years ago
5

An object moves in one dimension according to the function x(t)=13at3, where a is a positive constant with units of ms3. During

this motion, a force F⃗ =−bv is exerted on the object, where v is the object’s velocity and b is a constant with units of kgs. Which of the following expressions will yield the amount of energy dissipated by this force during the time interval from t=0 and t=T ?
A− 19ba2T5
B− 15ba2T5
C− 13ba2T5
D− ba2T5
Physics
1 answer:
9966 [12]3 years ago
7 0

Answer:

B) 1/5 ba^2 T^5

Explanation:

The dissipated energy is given by the work done over the object by the force F=-bv. The work is given by the following formula:

dW=Fdx

you derivative the function f(x) and replace v by the derivative dx/dt you obtain:

v=\frac{dx}{dt}=at^2\\\\dx=at^2dt\\\\W=\int_0^{T} Fdx=-\int_0^Tvbdx=-\int_0^Tb(at^2)(at^2dt)\\\\W=-ba^2\frac{T^5}{5}=-\frac{1}{5}ba^2T^5

hence, the dissipated energy is 1/5 ba^2 T^5

You might be interested in
What are the consequences of fertilizing chemicals in water?
Archy [21]
It can cause the water to create algae.
5 0
3 years ago
Faraday's law states that voltage can be changed by moving the coil out of the magnetic field true or false
NNADVOKAT [17]

As per Faraday's law of induction we know that induced EMF in a conducting closed loop is equal to rate of change in flux in that loop

So here we have

V = \frac{d\phi}{dt}

now when we move out a coil from magnetic field then in this case there will be EMF induced in that coil as here magnetic flux is changing with time linked with the coil.

Now this induced voltage will remain constant if coil is moved out uniformly

But it will not remain constant if coil is moved out with non uniform speed

So this statement is not always true

so answer must be

<u>FALSE</u>

8 0
3 years ago
A centrifuge in a medical laboratory rotates at an angular speed of 3,650 rev/min. when switched off, it rotates through 48.0 re
AlladinOne [14]
First of all we need to convert everything into SI units.

Let's start with the initial angular speed, \omega _i = 3650 rev/min. Keeping in mind that
1 rev = 2 \pi rad
1 min=60 s
we have
\omega _i = 3650  \frac{rev}{min} \cdot  \frac{2 \pi rad/rev}{60 s/min} =382.0 rad/s

And we should also convert the angle covered by the centrifuge:
\theta = 48.0 rev= 48.0 rev \cdot  2 \pi  \frac{rad}{rev}=301.4 rad

This is the angle covered by the centrifuge before it stops, so its final angular speed is \omega_f =0.

To solve the problem we can use the equivalent of
2aS = v_f^2 -v_i^2
of an uniformly accelerated motion but for a rotational motion. It will be
2 \alpha \theta = \omega_f^2-\omega_i^2
And by substituting the numbers, we can find the value of \alpha, the angular acceleration:
\alpha=- \frac{\omega_i^2}{2 \theta}=- \frac{(382 rad/s)^2}{2 \cdot 301.4 rad}=-242.1 rad/s^2
4 0
3 years ago
You are in a spacecraft moving at a constant velocity. The front thruster rocket fires incorrectly, causing the craft to slow do
Alchen [17]

Answer:

It continue to move forward at a constant velocity which will be slower than before the front thruster was fired.

Explanation:

Before the front thruster was fired, the spacecraft was already moving at a particular velocity.

After the malfunction, the front thruster is fired and then the force exerted by that front thruster slows the spacecraft down, as we are told.

By using the rear thruster to exert a force equal to that from the front thrusters, a force equal in magnitude to that of the front thrusters is added, cancelling out the effect of the front thrusters. Because the spacecraft is already moving at a slower speed at this point compared to the beginning, it continues to move at that speed.

8 0
3 years ago
A particle with charge Q and mass M has instantaneous speed uy when it is at a position where the electric potential is V. At a
olga nikolaevna [1]

Answer:

A

Explanation:

Ke = 1/2 MV^2

4 0
3 years ago
Other questions:
  • 6. For the following graph what can you conclude about the force applied to cause the object’s motion? Explain your reasoning
    11·2 answers
  • A football player pushes against another player trying to block him from moving any farther down the field. Which term best desc
    5·1 answer
  • If the loop sits in a uniform magnetic field of 3.5~T3.5 T that is oriented in the horizontal +x direction, what is the magnitud
    14·1 answer
  • A projectile is fired in such a way that its horizontal range is equal to 13.5 times its maximum height. What is the angle of pr
    9·2 answers
  • Which sentence from the article explains why we don't get a static electric shock every time we
    8·1 answer
  • The type of lens that spreads out parallel light is a
    9·1 answer
  • 28. Ken and Musa shared a cake such that Ken got twice the size
    12·1 answer
  • If you run North for 5 meters and then East for 15 meters and then
    11·1 answer
  • If 50000 J of heat are added during a Isothermal process, where the volume goes from 4 L to 6 L and the pressure goes from 36000
    10·1 answer
  • A projectile is fired with a velocity of 400 ms-1 at an angle of 30° to the horizontal. Find the time to reach the greatest heig
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!