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Mars2501 [29]
3 years ago
5

An object moves in one dimension according to the function x(t)=13at3, where a is a positive constant with units of ms3. During

this motion, a force F⃗ =−bv is exerted on the object, where v is the object’s velocity and b is a constant with units of kgs. Which of the following expressions will yield the amount of energy dissipated by this force during the time interval from t=0 and t=T ?
A− 19ba2T5
B− 15ba2T5
C− 13ba2T5
D− ba2T5
Physics
1 answer:
9966 [12]3 years ago
7 0

Answer:

B) 1/5 ba^2 T^5

Explanation:

The dissipated energy is given by the work done over the object by the force F=-bv. The work is given by the following formula:

dW=Fdx

you derivative the function f(x) and replace v by the derivative dx/dt you obtain:

v=\frac{dx}{dt}=at^2\\\\dx=at^2dt\\\\W=\int_0^{T} Fdx=-\int_0^Tvbdx=-\int_0^Tb(at^2)(at^2dt)\\\\W=-ba^2\frac{T^5}{5}=-\frac{1}{5}ba^2T^5

hence, the dissipated energy is 1/5 ba^2 T^5

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Nataliya [291]

Answer:

C)You should use the thin cooking twine.

Explanation:

A)You can choose either because they are the same length and will produce the same wave speed.

B)You should use the heavy rope.

C)You should use the thin cooking twine.

The speed of wave in a string is given by the following formula:

|v| = \sqrt{\frac{F_T}{u} }

Where |v| = speed of wave, F_T = tension in the string, and μ = mass per length of the string.

<em>Even though the two strings have the same length, the μ (mass/length) for the heavy rope will be more than the that of a thin rope. Consequently, the </em>F_T<em>:μ for the thin rope will be higher than that of the heavy rope and as such, gives a bigger |</em>v<em>|. </em>

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The correct option is C.

3 0
3 years ago
ANSWER AND I WILL BUY A CAR
Natali [406]
You are exerting 100N. Since there’s no NET force, then there must be exactly 100N pushing exactly back on your 100N to cancel it to exactly zero. Newton's first law states that whether a body is at rest or travelling in a straight line at a constant speed, it will remain at rest or continue to move in a straight line at a constant speed unless acted upon by a force.
8 0
3 years ago
A projector is placed on the ground 22 ft. away from a projector screen. A 5.2 ft. tall person is walking toward the screen at a
Stella [2.4K]

Answer:

y = 67.6 feet,   y = 114.4/ (22 - 3t)

Explanation:

For this exercise let's use that light travels in a straight line and some trigonometric relationships, the symbols are in the attached diagram

Large triangle Projector up to the screen

         tan θ = y / L

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         tan θ = y₀ / (L-d)

The angle is the same, so we equate the two equations

         y₀ / (L -d) = y / L

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we replace

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This is the equation of the shadow height change as a function of time

For the suggested distance the shadow has a height of

           y = 114.4 / (22-13)

           y = 67.6 feet

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The light bulb converts electrical energy into light and heat. 


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