Answer:
Explanation:
<u>1) Data:</u>
a) mass of solute = ?
b) volume of solution = 1.25 liter
c) M = 2.92 mol/liter
d) solute NaOH
<u>2) Formulae:</u>
<u />
a) Molarity, M = number of moles of solute / volume of solution in liters
b) mass in grams = molar mass × number of moles
<u>3) Solution:</u>
a) <u>Calculate number of moles of solute</u>:
- M = number of moles of solute / volume of solution in liters
⇒ number of moles of solute = M × volume of solution in liters
⇒ number of moles of solute = 2.92 mol/liter × 1.25 liter = 3.65 mol
b) <u>Molar mass of NaOH = 39.997 g/mol </u>(you can take this number from internet or calculate it using the atomic masses of Na, O, and H).
c) <u>Calculate the mass of solute:</u>
- mass in grams = molar mass × number of moles = 39.997 g/mol × 3.65 mol = 145.98905 g = 146. g
The answer must be reported with 3 significant figures, so it is 146. g.
They’re going to increase in atomic size based on how many electrons they have. You should be able to look at a periodic table or just look up how many electrons each of them has and then you can put it in that order
I believe the statement given above is true. When solid mercury (ii) nitrate is being heated, a decomposition reaction happens. The solid would decompose into 3 different substances - solid mercury (ii) oxide, gaseous nitrogen dioxide, and oxygen. The balanced chemical reaction would be written as:
2Hg(NO3)2 = 2HgO + 4NO2 +O2
<span>Decomposition reaction is a type of reaction
where it involves a single compound breaking down into two or more products.
These reactions often requires an energy source thus it is an endothermic
reaction. This is evident for this reaction since we supplied heat to the reactant for the reaction to proceed.</span>
Answer:
- the specific gravity of the block is 0.75
- the specific gravity of the solution is 1.5
Explanation:
Given the data in the question;
first we find the specific gravity of a block SGB
SGB = ( block vol below / total block vol ) × the specific gravity of water
we substitute
SG
= ( 1.5 / (1.5 + 0.5 ) ) × 1
SG
= ( 1.5 / (1.5 + 0.5 ) ) × 1
SG
= (1.5 / 2) × 1
SG
= 0.75
Therefore, the specific gravity of the block is 0.75
specific gravity of solution SG
SG
= (total block vol / block below ) × SG![_{BLOCK](https://tex.z-dn.net/?f=_%7BBLOCK)
we substitute
SG
= ( 2 / 1 ) × 0.75
SG
= 2 × 0.75
SG
= 1.5
Therefore, the specific gravity of the solution is 1.5