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GarryVolchara [31]
3 years ago
15

When a forklift raises an object, is it doing positive or negative work on the object? Which type of work is the force of gravit

y doing on the object? a)The forklift is doing negative work on the object because the direction of force and the direction of motion are the same. The force of gravity is doing positive work on the object because it is acting opposite to the direction of motion. b)The forklift is doing positive work on the object because the direction of force and the direction of motion are the same. The force of gravity is doing negative work on the object because it is acting opposite to the direction of motion. c)The forklift is doing positive work on the object because the direction of force and the direction of motion are the same. The force of gravity is doing positive work on the object because it is acting opposite to the direction of motion. d)The forklift is doing negative work on the object because the direction of force and the direction of motion are the same. The force of gravity is doing negative work on the object because it is acting opposite to the direction of motion.
Physics
1 answer:
Alja [10]3 years ago
6 0

Answer: B

The forklift is doing positive work on the object because the direction of force and the direction of motion are the same. The force of gravity is doing negative work on the object because it is acting opposite to the direction of motion. 

Explanation: The work done in lifting an object up is positive when the direction of the displacement and the force applied are in the same direction.

The work will be negative if force and direction of the motion are opposite to each other.

Also, force of gravity is considered positive when an object is moving toward the gravity. That is coming downward. Otherwise, it's negative when it's moving in the opposite direction.

When a forklift raises an object, the forklift is doing positive work on the object because the direction of force and the direction of motion are the same. The force of gravity is doing negative work on the object because it is acting opposite to the direction of motion.

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Answer:

<em><u>Solid</u> is the state in which matter maintains a fixed volume and shape; liquid is the state in which matter adapts to the shape of its container but varies only slightly in volume; and gas is the state in which matter expands to occupy the volume and shape of its container.</em>

7 0
2 years ago
Through what angle in degrees does a 33 rpm record turn in 0.32 s?<br> 63°<br> 35°<br> 46°<br> 74°
Darina [25.2K]

Answer:

1 rev = 2(pi) rad  pi(rad) = 180 degrees

so 33 rev/min * 1 min/60s * (2*pi)rad/1 rev *180 deg/ pi rad * .32 s = 63.36 degrees

Explanation:

63.36 estimated to 63 so 63

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2 years ago
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Answer:

B) The entropy is greater in the second state, with the gas on both sides of the box.

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3 0
3 years ago
Q7) A box sliding with a velocity of 5 m/s accelerates at 2 m/s^2. How
grigory [225]

Answer:

The box displacement after 6 seconds is 66 meters.

Explanation:

Let suppose that velocity given in statement represents the initial velocity of the box and, likewise, the box accelerates at constant rate. Then, the displacement of the object (\Delta s), in meters, can be determined by the following expression:

\Delta s = v_{o}\cdot t+\frac{1}{2}\cdot a\cdot t^{2} (1)

Where:

v_{o} - Initial velocity, in meters per second.

t - Time, in seconds.

a - Acceleration, in meters per square second.

If we know that v_{o} = 5\,\frac{m}{s}, t = 6\,s and a = 2\,\frac{m}{s^{2}}, then the box displacement after 6 seconds is:

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5 0
3 years ago
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insens350 [35]

Answer:

24.531 m

Explanation:

t = Time taken = 1.7 s

u = Initial velocity = 6.1 m/s

v = Final velocity

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Equation of motion

s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=6.1\times 1.7+\dfrac{1}{2}\times 9.8\times 1.7^2\\\Rightarrow s=24.531\ m

The initial height of the rock above the ground is 24.531 m

7 0
3 years ago
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